Name one person in hxh that is attracted to gon yes the seually attracted

Hey! I’m struggling and need help! Thank you!

Charra [1.4K]

Answer:

That would be obtuse

Step-by-step explanation:

Those are all more than 90 degrees!

4 0

2 years ago

HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!! CERTAIN ANSWERS AND I WILL MARK YOU AS BRAINIEST!!!! WISH YOU BEST OF LUCK HOPEFULLY ITS N

AURORKA [14]

Answer:

1)

Minimum is a 4th Degree

2)

Positive; Even

3)

$x=-4, -1\text{ Odd Multiplicity}\\x=3\text{ Even Multiplicity}$

Step-by-step explanation:

Part 1)

The minimum degree of our function will be 4.

Looking at the graph, we know that the graph crosses the x-axis at -4 and -1. Since it crosses through the x-axis at these two points, these two factors must have an odd multiplicity.

So, it can be anything 1, 3, 5, 7, etc.

However, we will choose the lowest one, 1.

Next, we know that the graph bounces off at 3.

So, it must have an even multiplicity. In other words, 2, 4, 6, 8, etc.

We choose the lowest one, 2.

Therefore, the minimum degree of our function will be 1+1+2 or 4.

Part 2)

The degree of our polynomial is (and will always be) even. Therefore, both ends of the graph will go in the same direction.

Recall the simplest even polynomial, the parent quadratic function. When the leading coefficient is positive, both of the ends go straight up.

This applies to all polynomials with even degrees.

Therefore, since the arms of the graph is going straight up towards positive infinity, the leading coefficient of our graph must be positive.

Part 3)

This is similar to Part 1.

We can see that the graph touches the x-axis at -4, -3, and 1. So, the zeros of the function is: $x=-4, -1, 3$

We know that it passes through $x=-4 \text{ and } x=-1$ . So, these two factors must have an odd multiplicity.

However, since the graph bounces off $x=3$ , this factor must have an even multiplicity.

And we're done!

7 0

3 years ago

Police use photographs of various facial features help witnesses identify suspects. One basic identification kit contains 195 ha

algol [13]

Answer:

the kit can produce 99*89*105*74 = 68,461,470 faces

Step-by-step explanation:

Hope this helps : )

7 0

3 years ago

The total length of pencils A, B and C is 29 cm. Pencil a is 11 cm shorter then pencil B, and pencil B is twice as long a pencil

satela [25.4K]

The length of pencil A is 5 cm

Solution:

Let the length of pencil A be "x"

Let the length of pencil B be "y"

Let the length of pencil C be "z"

The total length of pencils A, B and C is 29 cm

Therefore,

length of pencil A + length of pencil B + length of pencil C = 29

x + y + z = 29 ------------ eqn 1

Pencil A is 11 cm shorter then pencil B

x = y - 11 ------- eqn 2

Pencil B is twice as long a pencil C

y = 2z

$z = \frac{y}{2}$ ------ eqn 3

Substitute eqn 2 and eqn 3 in eqn 1

$y - 11 + y + \frac{y}{2} = 29\\\\2y + \frac{y}{2} = 29 + 11\\\\\frac{4y+y}{2} = 40\\\\5y = 80\\\\y = 16$

Substitute y = 16 in eqn 2

x = 16 - 11

x = 5

Thus length of pencil A is 5 cm

5 0

3 years ago

Sandra is opening a savings account which compounds interest quarterly. Her banker gave her the following function to find the a

aksik [14]

A ..... Because .....

8 0

3 years ago