Two dams, when opened, release water at different rates. The following functions represent the amounts of water the dams release
1 answer:
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Answer:
a.) y = 3/(2ˣ)
b.) y = 1/(2ˣ)
c.) y = (π^π)ˣ
d.) y = (1/27)(1/√(3))ˣ
e.) y = .002908/(.119025ˣ)
f.) y = .00000004808/(.0413ˣ)
Step-by-step explanation:
Concept need to know is:
- a negative exponent will flip the numerator with the denominator
- a fraction as an exponent is just a root. so if the exponent is x^(1/2) then the root is 2 and x^(1/3) is a cube root
- adding and subtracting exponent is the same thing as multiplying the same base.
- so x^(1+2) = (x^1)(x^2)
- and x^(1-2) = (x^1)(x^-2)
First flip the bottom fraction:
After you simplify further you get:
After you simplify further you get: