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4 years ago

9

a vet weighs two puppies the small puppy weighs 4 1/2 pounds the large puppy weighs 4 2/3 times as much as the small puppy how m

uch does the large puppy weigh

2 answers:

Llana [10]4 years ago

7 0

The large puppy weighs 20.97 Pounds. This is because 2/3 of a hundred is 66. You would do 4.5 Times 4.66. This equals 20.97. It can be rounded to 21. Hope this helps!

ICE Princess25 [194]4 years ago

5 0

Answer:

<h2>The large puppy weighs 21 pounds.</h2>

Step-by-step explanation:

Givens

The small puppy weighs 4 1/2 pounds.
The large puppy weighs 4 2/3 times as much as the small puppy.

First, we need to transform each mixed number into fractions

$4\frac{1}{2}=\frac{9}{2}\\4\frac{2}{3}=\frac{14}{3}$

Now, the situation can be expressed as

$L=\frac{14}{3}S$

Where $L$ is the large puppy and $S$ is the small puppy.

And we know $S=\frac{9}{2}$

Replacing this value, we have

$L=\frac{14}{3} \times \frac{9}{2}=\frac{126}{6} =21$

Therefore, the large puppy weighs 21 pounds.

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jasenka [17]

Answer:

42.39 sq.cm

Step-by-step explanation:

Ф = 135°

r = 6 cm

Area of the sector = $\frac{theta}{360}*\pi *r^{2}\\$

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6 0

3 years ago

Read 2 more answers

Round 869907 to the nearest hundredth

Luden [163]

869,907 when rounded to the nearest hundredth = 869,900

5 0

3 years ago

Aisha estimates the product of 12 and 2.4 by rounding 2.4 to the nearest whole.

Tanya [424]

Answer:

24

Step-by-step explanation:

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8 0

2 years ago

The Slow Ball Challenge or The Fast Ball Challenge.

cupoosta [38]

Answer:

Fast ball challenge

Step-by-step explanation:

Given

Slow Ball Challenge

$Pitches = 7$

$P(Hit) = 80\%$

$Win = \$60$

$Lost = \$10$

Fast Ball Challenge

$Pitches = 3$

$P(Hit) = 70\%$

$Win = \$60$

$Lost = \$10$

Required

Which should he choose?

To do this, we simply calculate the expected earnings of both.

Considering the slow ball challenge

First, we calculate the binomial probability that he hits all 7 pitches

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

Where

$n = 7$ --- pitches

$x = 7$ --- all hits

$p = 80\% = 0.80$ --- probability of hit

So, we have:

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

$P(7) =^7C_7 * 0.80^7 * (1 - 0.80)^{7 - 7}$

$P(7) =1 * 0.80^7 * (1 - 0.80)^0$

$P(7) =1 * 0.80^7 * 0.20^0$

Using a calculator:

$P(7) =0.2097152$ --- This is the probability that he wins

i.e.

$P(Win) =0.2097152$

The probability that he lose is:

$P(Lose) = 1 - P(Win)$ ---- Complement rule

$P(Lose) = 1 -0.2097152$

$P(Lose) = 0.7902848$

The expected value is then calculated as:

$Expected = P(Win) * Win + P(Lose) * Lose$

$Expected = 0.2097152 * \$60 + 0.7902848 * \$10$

Using a calculator, we have:

$Expected = \$20.48576$

Considering the fast ball challenge

First, we calculate the binomial probability that he hits all 3 pitches

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

Where

$n = 3$ --- pitches

$x = 3$ --- all hits

$p = 70\% = 0.70$ --- probability of hit

So, we have:

$P(3) =^3C_3 * 0.70^3 * (1 - 0.70)^{3 - 3}$

$P(3) =1 * 0.70^3 * (1 - 0.70)^0$

$P(3) =1 * 0.70^3 * 0.30^0$

Using a calculator:

$P(3) =0.343$ --- This is the probability that he wins

i.e.

$P(Win) =0.343$

The probability that he lose is:

$P(Lose) = 1 - P(Win)$ ---- Complement rule

$P(Lose) = 1 - 0.343$

$P(Lose) = 0.657$

The expected value is then calculated as:

$Expected = P(Win) * Win + P(Lose) * Lose$

$Expected = 0.343 * \$60 + 0.657 * \$10$

Using a calculator, we have:

$Expected = \$27.15$

So, we have:

$Expected = \$20.48576$ -- Slow ball

$Expected = \$27.15$ --- Fast ball

<em>The expected earnings of the fast ball challenge is greater than that of the slow ball. Hence, he should choose the fast ball challenge.</em>

5 0

3 years ago

(NO FILES OR LINKS OR RANDOM WORDS)

ehidna [41]

Answer:

Randomly selecting a six of diamonds - 1 / 52

Randomly selecting a 7, 8, 9 or 10 - 4 / 13

Step-by-step explanation:

There is only 1 six of diamonds in a standard deck of cards. There are 52 cards in a deck, thus the probability of pulling a six of diamonds is 1 in 52.

There are 4 of each card in a deck. so they are 4 7's, 4 8's. 4 9's and 4 10's. And there are a total of 52 cards in a deck. So the probability of pulling a 7,8,9 or 10 are 4 + 4 + 4 + 4 in 52

4 + 4 + 4 + 4 = 16

16 / 52 simplified is 4 / 13 Therefore the is a 4 in 13 chance of pulling a 7 8 9 or 10

The other ones are correct

3 0

3 years ago