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4 years ago

In three to five sentences, evaluate the scientific evidence that supports the big bang theory and the steady state theory.

Physics

1 answer:

zloy xaker [14]4 years ago

3 0

Answer:

you are capping I know what is the answer

Explanation:

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Resistor A has twice the resistance of resistor B. The two are connected in series and a potential difference is maintained acro

Ainat [17]

Answer:

The thermal energy dissipated in A would be twice that in B

Explanation:

Resistor B (RB)= R

Resistor A (RA)= 2 R

When they are connected in series the equivalent Resistance in the circuit would be;

Equivalent resistance = RA +RB = R + 2 R = 3 R;

From ohms law I = V/R

I = V/3 R

Now the thermal energy is the power dissipated by the circuit and can be obtained thus;

P = $I^{2}R$

Then,

$P_{A} = (\frac{V}{3R}) ^{2} *2 R\\\\P_{A} = \frac{V^{2} }{9R^{2} } *2R\\\\P_{A} = \frac{2}{9}( \frac{V^{2} }{R}) \\\\P_{B} = (\frac{V}{3R}) ^{2} * R\\\\P_{B} = \frac{V^{2} }{9R^{2} } *R\\\\P_{B} = \frac{1}{9}( \frac{V^{2} }{R})$

Therefore Pa : Pb = 2: 1, this means that the thermal energy dissipated in A would be twice that in B

4 0

3 years ago

Increasing the mass attached to a spring will decrease the angular frequency of its vibrations. True or False

Scrat [10]

Answer:

decreases

Explanation:

The angular frequency of the mass is given by

$\omega =\sqrt{\frac{k}{m}}$

where, k is the spring constant and m be the mass of the body which is doing oscillations.

if the mass of the body increases, so the value of angular frequency decreases, as the angular frequency is inversely proportional to the square root of the mass of the body.

4 0

3 years ago

The moon has a mass of 7.35x1022 kg and is a lot farther away than is shown in textbooks. The mass of the

anyanavicka [17]

Answer:

$F=1.98\times 10^{20}\ N$

Explanation:

Given that,

The mass of a Moon, $M_m=7.35\times 10^{22}\ kg$

The mass of the Earth, $M_e=5.98\times 10^{24}\ kg$

The moon's mean orbit distance around the earth is, $r=3.84\times 10^8\ m$

We need to find the gravitational force exerted on the moon by the Earth.

The formula of gravitational force is given by :

$F=G\dfrac{M_mM_e}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{7.35\times 10^{22}\times 5.98\times 10^{24}}{(3.84\times 10^8)^2}\\\\F=1.98\times 10^{20}\ N$