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tino4ka555 [31]
3 years ago
8

Whats the Answer y=10 4x-5y=3

Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0
4x-5y=3
4x-5(10)=3
4x-50=3
+50 +50
4x=53
/4 /4

x=53/4
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Drag each equation to show if it could be a correct first step to solving the equation
forsale [732]

Answer:

<u>Yes</u>

  • (2 · x) + (2 · 7) = 36
  • x + 7 = 18
  • 2x + 14 = 36

<u>No</u>

  • 2x + 7 = 36
  • 2(x + 7) = 72
  • x + 14 = 36

Step-by-step explanation:

It is appropriate to eliminate parentheses as a first step. This can be done using the distributive property, resulting in either of ...

  • 2x +2·7 = 36
  • 2x +14 = 36 . . . . . 2·7 evaluated mentally

or by dividing the equation by the factor outside parentheses, resulting in ...

  • x + 7 = 18

___

Any of the equations other than these represent violations of the equal sign. Something has been done to one side of the equation without the same thing being done to the other side.

5 0
4 years ago
The image shows a circle centered at point O. Angle AOB measures 50 degrees. What is the measure of angle ACB?
sveticcg [70]

Answer:

b) ∠ACB = 25 degrees

Step-by-step explanation:

arc BA = 50° because central angle AOB = 50°

∠ACB is inscribed angle of 50°, so it is (1/2)(50) = 25°

5 0
3 years ago
Given: Trapezoid EFGH with vertices El-5.3).(-3.3). G(-1.1). and H(-6.1) as shown in the diagram below.
sergij07 [2.7K]

Answer: 5, -3

Step by Step Explaination:

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3 years ago
Find the volume of the composite figure to the nearest tenth. Use 3.14 for pi.
Vilka [71]

Given:

In the given fig,

The radius of the cylinder = 15 ft

The height of the cylinder = 26 ft

The height of the cone = 21 ft

The radius of the cone = 15 ft

To find the volume of the cone, the volume of the cylinder and the composite figure.

Formula

The volume of the given composite fig is

V = V_{1} +V_{2}

where, V_{1} be the volume of the cone.

V_{2} be the volume of the cylinder.

V_{1} = \frac{1}{3} \pi r^{2} h, r be the radius and h be the height.

V_{2} = \pi r^{2} h, r be the radius and h be the height.

Now,

Putting, r = 15, h = 21 and π = 3.14 we get,

V_{1} = \frac{1}{3} (3.14)(15^{2} )(21) cube ft

V_{1} = 4945.5 cube ft

Again,

Putting,

V_{2} = (3.14)(15^{2} )(26) cube ft

V_{2} = 18369 cube ft

Therefore, the volume of the composite fig = (4945.5+18369) cube ft = 23314.5 cube ft

Hence,

a) The volume of the cone is 4945.5 cube ft.

b) The volume of the cylinder is 18369 cube ft.

c) The volume of the composite figure is 23314.5 cube ft.

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The quotient of a number increased by 9 and 4 is -2
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