c = cost of food/med for cats
d = cost of food/med for dog
y = total cost/spent
What you know:
y = 6c + d [has 6 cats and 1 dog]
c = 2/3d - 5 [cost for cat is 5 less than 2/3 cost for dog]
y = $195
y = 6c + d
Substitute/plug in what you know, plug in (2/3d - 5) for c and 195 for y
195 = 6(2/3d - 5) + d Distribute/multiply 6 into (2/3d - 5)
195 = 4d - 30 + d Combine like terms
195 = 5d - 30 Add 30 on both sides of the equation
225 = 5d Divide 5 on both sides
$45 = d
Answer:
I would increase the number and multiply
Step-by-step explanation:
Step-by-step explanation:
1. Since 39 is 3/5 of the club, divide by 3 to get 1/5 of the club
2. 1/5 of the club is 13 people
3. Multiply 13 by 5 to get 5/5 of the club (which is the whole club)
4. The whole club is 65 people
5. You can check it because 65×3/5=39
Answer:
10 tacos costs $15.00
Step-by-step explanation:
I like to use ratio's to solve this type of problem. I will put cost over number of tacos.
$6.00 x dollars
-------- = --------------
4 tacos 10 tacos
Using cross products
6 * 10 = 4 * x
60 = 4x
Divide each side by 4
60/4 = 4x/4
15 =x
10 tacos costs $15.00
