The minimum surface area that such a box can have is 380 square
<h3>How to determine the minimum surface area such a box can have?</h3>
Represent the base length with x and the bwith h.
So, the volume is
V = x^2h
This gives
x^2h = 500
Make h the subject
h = 500/x^2
The surface area is
S = 2(x^2 + 2xh)
Expand
S = 2x^2 + 4xh
Substitute h = 500/x^2
S = 2x^2 + 4x * 500/x^2
Evaluate
S = 2x^2 + 2000/x
Differentiate
S' = 4x - 2000/x^2
Set the equation to 0
4x - 2000/x^2 = 0
Multiply through by x^2
4x^3 - 2000 = 0
This gives
4x^3= 2000
Divide by 4
x^3 = 500
Take the cube root
x = 7.94
Substitute x = 7.94 in S = 2x^2 + 2000/x
S = 2 * 7.94^2 + 2000/7.94
Evaluate
S = 380
Hence, the minimum surface area that such a box can have is 380 square
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Q. The area of David's living room is 18.087 square yards, and their bedroom has an area of 15.78 square yards.Round to the nearest tenth and estimate the amount of carpet they need to buy. PLZ HELP!!
A. 33.867 and rounded is 33.9
Answer:
32 inches^3
Step-by-step explanation:
Volume = 1/2 ( base x height x length)
0.5 ( 4 x 2 x 8) = 32 inches^3
Answer:
c
Step-by-step explanation:
Pythagoras theroem
= 4√73
Answer: the diameter is 7cm And the radius is 3.5 cm
Step-by-step explanation:
