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miss Akunina [59]
3 years ago
9

Is my answer correct ??

Mathematics
2 answers:
Mariulka [41]3 years ago
7 0
Yes that would be incorrect, it needs to be 10
Tpy6a [65]3 years ago
5 0

The largest triangle and the triangle whose hypotenuse is x are similar. So:

(21 + 4)/x = x/4

Cross multiply:

x^2 = 100

x = 10

Your answer is incorrect. It should be 10, not 20.

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Cuatro meses después que se detuviera la publicidad, una compañia fabricante notifica que sus ventas han cai­do de 100.000 unida
Volgvan

Answer:

51,200 unidades

Step-by-step explanation:

Paso 1

Calculamos el porcentaje de disminución

= 100000 - 80000/100000 × 100

= 20000/100000 × 100

= 20%

Por lo tanto, el porcentaje de disminución cada mes = 20%

Paso 2

La fórmula de la disminución exponencial

y = a (1 - r) ^ t

a = 80.000

r = 20% = 0,2

t = tiempo en meses = 2

y = 80000 (1 - 0,2) ^ 2

y = 51.200 unidades

7 0
3 years ago
1/3 + 5/6 + 5/12 What is the answer
SOVA2 [1]
1/3 + 5/6 + 5/12

1.583333333333333
3 0
3 years ago
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Tj worked for 5 hours and 45 minutes how should he write that on his time card
matrenka [14]

Answer:

Tj should write 5.75 hours on her time card.

Step-by-step explanation:

We have been given, Tj worked for 5 hours and 45 minutes.

We will convert 45 minutes to hours by dividing 45 by 60 as one hour has 60 minutes.

\frac{45 minutes }{60} \times\frac{hour}{minutes}

=0.75 hours

Hence, Tj should write 5.75 hours on her time card.

4 0
3 years ago
Question regarding logarithms.
Eddi Din [679]

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\left(-\dfrac{49}{343}-\dfrac{1}{343}\right)\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\\\\-\dfrac{50}{343}\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\qquad\text{multiply both sides by}\ \left(-\dfrac{25}{14}\right)\\\\\dfrac{50\cdot25}{343\cdot14}\cdot7^{x-2}=5^{x-2}\qquad\text{divide both sides by}\ 7^{x-2}\\\\\dfrac{25\cdot25}{343\cdot7}=\dfrac{5^{x-2}}{7^{x-2}}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}

\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}

6 0
3 years ago
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Solve for the values of x and y.
Tasya [4]

Answer:

We can’t solve for x and y

Step-by-step explanation:

5 0
3 years ago
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