Question

part A: is x=6 a solution of the equation 8x+18=56? Explain. Part B: suppose the solution x=6 increases to x=9, and the left side of the equation stays the same. How would the right side need to change if the solution is no x=9?

Answer 1

$8x = 56 - 18$
$8x = 38$
$x = 4.75$
$4.75 = no \: 6$
part b

the right part will become 90
$8x(9) + 18 = 90$
$72 + 18 = 90$
$90 = 90$