May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
See below for solution. Hope this is helpful
6x+1 = 3(2x-4)
-4(x+3) = 4(x-1)
Answer:
1/8
Step-by-step explanation:
<u>Solving in steps:</u>
- x(8x - 8y)⁻¹ + y(8y - 8x)⁻¹ =
- x/8(x-y) +y/8*(-(x-y))
- x/8(x-y) - y/8(x-y) =
- (x -y)/8(x-y) =
- 1/8
Answer is 1/8
0.25r-0.125+0.5r=0.5r
0.75r-0.125=0.5r
-0.125= -0.25r
r=0.5
