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Misha Larkins [42]
3 years ago
11

HELP!!!!!!!!! Function or not????

Mathematics
2 answers:
zaharov [31]3 years ago
8 0

Answer: This is a function

Step-by-step explanation: It passes for the vertical line test.

uranmaximum [27]3 years ago
3 0
Yes, it’s a function
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10 points question:
Tpy6a [65]
Hi there! Mind trick question again...
The answer is 0.4624159615452.

I hope this is correct! Have a great day!

3 0
4 years ago
Adrian jogs 3/4 mile each morning how many days will take to jog 3 miles
lbvjy [14]
----------------------------------------------------------------
Given Information
----------------------------------------------------------------
Adrian can run 3/4 mile in 1 morning.

----------------------------------------------------------------
Find how long he needs to run 1 mile
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3/4 miles = 1 morning 

[ Divide by 3/4 on both side ]
3/4 ÷ 3/4 miles = 1 ÷ 3/4

1 miles = 4/3 morning

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Find how long he needs to take to run 3 miles
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1 miles = 4/3 morning

[ multiply by 3 through ]
3 miles = 4/3 x 3 
3 miles = 4 mornings 

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Answer : 4 mornings
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6 0
3 years ago
The table shows conversions for common units of length.
Vedmedyk [2.9K]

Answer:

1 kilometer

0.621371 miles

Step-by-step explanation:

Given data

In the given table we are presented with the conversion table for common units and we are required to present the conversion for kilometers to miles

Hence the conversion from kilometers to miles is presented below

1 kilometer

0.621371 mile

3 0
3 years ago
What is the number property of 17+0
vladimir1956 [14]

Answer:

The identity property

Step-by-step explanation:

anything added to 0 is itself.

8 0
3 years ago
What is the distance between the points (-6,5) and (8,-2) on a coordinate plane?
Naddik [55]

Distance Formula: D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Apply the points: D=\sqrt{(8-(-6))^2+((-2)-5)^2

Solve: D=\sqrt{(8-(-6))^2+((-2)-5)^2}\\D=\sqrt{14^2+(-7)^2}\\D=\sqrt{169+49}\\D=\sqrt{218}

Since the square root of 218 cannot be simplified, the answer is

D=\sqrt{218}

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

7 0
3 years ago
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