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ira [324]
3 years ago
15

What is the domain of y = sec(x)?

Mathematics
2 answers:
Andrei [34K]3 years ago
5 0

Answer:

\mathbb{R}-(n\pi+\frac{\pi}{2})

Step-by-step explanation:

We have, \text{y}=\text{sec} x

This can also be written as \text{y}=\frac{1}{\text{cos} x}

For this to be defined, \text{cos}x\neq 0

So, the function is defined for all real numbers except when \text{cos}x=0

i.e., for x=(2n+1)\frac{\pi }{2}\text{or}x=n\pi+\frac{\pi}{2}

Therefore, the domain of \text{y}=\text{sec} x is \mathbb{R}-(n\pi+\frac{\pi}{2})

OLEGan [10]3 years ago
3 0
<span>What is the domain of y = sec(x)?

Domain:
</span><span>All real numbers except pi/1 + n*Pi
</span>
Range:
<span>(-inf , -1] U [1 , + inf)</span>
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Answer:

Both Oscar and Kim will have enough to purchase the book.

Step-by-step explanation:

Oscar takes 30% of the normal price and subtracts it from the normal price. Out of 100% price he takes 30% so the result is: 100-30%= 70% of the normal price. Oscar's first step has the same result as Kim.

Oscar takes 10% of the discounted price (70%) and adds it back. The price will become 70% + 10%*70%= 77% of original price. Kim multiplies the discounted price with 110%, so the price will be: 70% * 110%= 77%. Both also give the same result.

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Oscar :

28.50 - 0.30(28.50) = 28.50 - 8.55 = 19.95

0.10(19.95) + 19.95 = 2 + 19.95 = 21.95

Kim :

0.7(28.50) = 19.95

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7 0
3 years ago
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The probability of Jane wins a game is 7/10. Jane plays a game 50 times. Find the number of times she is expected to win the gam
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2 years ago
Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a
dolphi86 [110]

Answer:

The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

Step-by-step explanation:

If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

P(x)=a(x-c_1)(x-c_2)...(x-x_n)

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)

R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2

R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2     [a^2-b^2=(a-b)(a+b)]

R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2

R(x)=(x^2-6x+18)(x^2-4x+4)                [i^2=-1]

R(x)=(x^2-6x+18)(x^2-4x+4)

R(x)=x^4-10x^3+46x^2-96x+72

Therefore the required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

3 0
3 years ago
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