For this case we have that by definition, the standard form of a linear equation is given by:
By definition, if two lines are perpendicular then the product of their slopes is -1. That is to say:
We have the following point-slope equation of a line:
The slope is:
We find the slope 
of a perpendicular line:
Thus, the equation is of the form:
We have the point through which the line passes:
Thus, the equation is:
We manipulate algebraically:
We add 3 to both sides of the equation:
We multiply by 2 on both sides of the equation:
We subtract 3x on both sides:
We subtract 12 from both sides:
ANswer:
Rsc . rrr . rrc rrs . rsr rcr crs src scr csr ccc sss
these are all the possible outcomes
12 total outcomes
Answer:
The measure of angle E is 45 degrees
Step-by-step explanation:
To get the measure if angle E, we use the appropriate trigonometric ratio
From the question, EF is the hypotenuse since it faces the right angle
EG is adjacent to angle E
so we are going to use the trigonometric ratio that connects adjacent to the hypotenuse
This trigonometric ratio is the cosine
It is the ratio of the adjacent to the hypotenuse
Thus,
we have it that;
Cos E = EG/EF
cos E = 6√26/12√13
E = arc Cos ( 6 √26/12 √13)
E = 45 degrees
Answer:
%82.5
Step-by-step explanation:
- The final exam of a particular class makes up 40% of the final grade
- Moe is failing the class with an average (arithmetic mean) of 45% just before taking the final exam.
From point 1 we know that Moe´s grade just before taking the final exam represents 60% of the final grade. Then, using the information in the point 2 we can compute Moe´s final grade as follows:
,
where FG is Moe´s Final Grade and FE is Moe´s final exam grade. Then,
.
So, in order to receive the passing grade average of 60% for the class Moe needs to obtain in his exam:
That is, he need al least %82.5 to obtain a passing grade.
