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Trava [24]
3 years ago
13

The domain and range of 5x squared plus 10x what is the domain and range of f of x equals 5x squared plus 10x

Mathematics
1 answer:
liberstina [14]3 years ago
8 0

Answer:

Domain:  set of all real numbers

Range:  y \geq  -5

Step-by-step explanation:

We have to find the domain and range of the function:

f(x) =5x^2+10x

This is a quadratic function, shape of a "U", that's called a parabola.

The domain is the set of x values for which the function is defined.

The range is the set of y values for which the function is defined.

Normally, any parabola in the form  ax^2+bx+c  has domain as "all real numbers". This is the case for this problem as well, thus,

Domain = set of all real numbers

Now, for the range, we have to look at the minimum value of the function. So, the range would be y values greater than or equal to the minimum number. Lets find the minimum value of this function.

We have to find the value of x for which the minimum occurs by using the formula:

x=\frac{-b}{2a} =\frac{-10}{2(5)} =-1

<em><u>Note: value of a is "5" and b is "10"</u></em>

Now, we plug this into the function to find the minimum value:

f(x)=5x^2+10x\\f(-1)=5(-1)^2 +10(-1)\\f(-1)=-5

So, the range is set of all real numbers greater than or equal to -5.

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3 years ago
Mr. Moore planted a tree in his backyard. His tree grew 3 1/3 feet over five years. if his tree grew at the same rate each year,
alina1380 [7]

Answer:

D. 2/3 per year.

Step-by-step explanation:

3 1

3

÷ 5

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4 0
3 years ago
Find a and b so that f(x) = x^3 + ax^2 + b will have a critical point at (2,3).
Digiron [165]

Using the critical point concept, it is found that a = -3 and b = 7.

<h3>What are the critical points of a function?</h3>
  • The critical points of a function are the values of x for which:

f^{\prime}(x) = 0

In this problem, the function is:

f(x) = x^3 + ax^2 + b

Hence, the derivative is:

f^{\prime}(x) = 3x^2 + 2ax

Then:

f^{\prime}(x) = 0

3x^2 + 2ax = 0

x(3x + 2a) = 0

x = 0

3x + 2a = 0

3x = -2a

x = -\frac{2a}{3}

Since the critical point is at x = 2, we have that:

-\frac{2a}{3} = 2

-2a = 6

2a = -6

a = -3

Then:

f(x) = x^3 - 3x^2 + b

Critical point at (2,3) means that when x = 2, y = 3, then:

3 = 2^3 - 3(2)^2 + b

8 - 12 + b = 3

b = 7

You can learn more about the critical point concept at brainly.com/question/2256078

4 0
2 years ago
On a 15 scale drawing of a car, one part is 88 inches long. How long will the actual car part be?
IrinaVladis [17]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

The lenght that <span>will the actual car part be is 40 inches. Below is the solution:
</span>
8" = 8 x 5 
= 40 inches
6 0
3 years ago
What is the absolute value of -22
Bond [772]
The absolute value of a number is always positive. It is the distance the number is away from zero.
|-22| = 22
8 0
3 years ago
Read 2 more answers
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