A petting zoo owner is building an enclosure for his farm animals. He needs 353 feet of fencing. The supply store sells fencing
2 answers:
Answer:
30 pieces of wire is needed.
Step-by-step explanation:
A petting zoo owner is building an enclosure for his farm animals.
He needs 353 feet of fencing. The supply store sells fencing in pieces 12 feet long.
The number of pieces needed = feet
This can be rounded to 30 pieces.
Hence, the answer is 30 pieces.
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Answer:
System of linear equations
a: adult ticket price and c: child ticket price
Step-by-step explanation:
This system of equations can be used to find the price of the adult and child tickets.
We have two equations (one for each day) and two unknowns (adult ticket price and child ticket price).
Let a: adult ticket price and c: child ticket price,
we have for the first day that 3 adult tickets and 1 child ticket adds $38:
and for the second day we have that 2 adult tickets and 2 child tickets adds $52:
If we write this as a system of equations, we have:
The value of constant a is -5
Further explanation:
We will use the comparison of co-efficient method for finding the value of a
So,
Given
As it is given that
(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28
In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x
Comparing coefficient of x^3
So the value of constant a is -5
Keywords: Polynomials, factorization
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