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3 years ago

36×36 show work use math alagrithem

Mathematics

1 answer:

amm18123 years ago

7 0

Answer:

1296

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Simplify 7(2x+y)+6(×+5y)

iris [78.8K]

Simplify, 7(2x+y)+6(x+5y).

a: 20x+37y

(7 • (2x + y)) + 6 • (x + 5y)

Step 2 :

Equation at the end of step 2 :

7 • (2x + y) + 6 • (x + 5y)

Step 3 :

Final result :

Thanks,

Deku ❤

4 0

3 years ago

5x +14+13x-2 i need help on these type of problems please

OleMash [197]

Answer:

18x+12

Step-by-step explanation:

5x+14+13x-2

combine Like terms:

5x+13x

14-2

18x+12

3 0

3 years ago

Read 2 more answers

Consider the following region R and the vector field F. a. Compute the two-dimensional curl of the vector field. b. Evaluate bo

Shalnov [3]

Looks like we're given

$\vec F(x,y)=\langle-x,-y\rangle$

which in three dimensions could be expressed as

$\vec F(x,y)=\langle-x,-y,0\rangle$

and this has curl

$\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle$

which confirms the two-dimensional curl is 0.

It also looks like the region $R$ is the disk $x^2+y^2\le5$ . Green's theorem says the integral of $\vec F$ along the boundary of $R$ is equal to the integral of the two-dimensional curl of $\vec F$ over the interior of $R$ :

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA$

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of $R$ by

$\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle$

$\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt$

with $0\le t\le2\pi$ . Then

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt$

$=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0$

7 0

3 years ago

Solve by unfolding: a0=2, and, n>=1, a_n=7a_n-1.

vodomira [7]

We are told that the first term is 2. The next term is 7(2) = 14; the third term is 7(14) = 98. And so on. So, the first term and the common ratio (7) are known.

The nth term of this geometric series is a_n = 2(7)^(n-1).

Check: What is the first term? We expect it is 2. 2(7)^(1-1) = 2(1) = 2. Correct.

What is the third term? We expect it is 98. 2(7)^(3-1) = 2(7)^2 = 98. Right.

6 0

3 years ago

1.) Which of the following expressions is the difference of two terms?

Step2247 [10]

Answer:

1.a

2.a

3.d

4.c

5.c

Step-by-step explanation:

sana makatulung po

8 0

3 years ago