Question

Pleasee help me 2t+ 1 = 3t-1 + 33 4​

Answer 1

Answer:

t = - 2

Step-by-step explanation:

$\frac{2t + 1}{3} = \frac{(3t-1) + 3}{4}$

First we need to cross multiply to get rid of the division to make it easier to solve.

Multiply 2t+1 by 4 and (3t-1) + 3 by 3

4 ( 2t + 1 ) = 3 ( ( 3t - 1 ) + 3 ) On the right we need to combine terms.

4 ( 2t + 1 ) = 3 ( 3t - 1 + 3 )

4 ( 2t + 1 ) = 3 ( 3t + 2 )   Multiply

4 * 2t + 4 * 1 = 3 * 3t + 3 * 2     Remember order of operations. Multiplication comes before addition and subtraction.

4 * 2t + 4 * 1 = 3 * 3t + 3 * 2

8t + 4 = 9t + 6      Subtract 8t from each side

8t - 8t + 4 = 9t - 8t + 6

4 = t + 6       Subtract 6 from each side

4 - 6 = t + 6 - 6

4 - 6 = t

- 2 = t

Answer 2

Answer:

t = -1

Step-by-step explanation:

$2t + 1 = 3t - 1 + 3$

Collect like terms and simplify

$2t - 3t = - 1 + 3 - 1 \\ - t = 1$

Divide through by -1

$\frac{ - t}{ - 1} = \frac{ 1}{ - 1} \\ t = - 1$