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Leno4ka [110]
1 year ago
5

For what value of x is r(x)= -21??

Mathematics
1 answer:
Naily [24]1 year ago
4 0

Answer:

Rx= - 21

Rx/r= - 21/r

X=-21/r

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Is it (sometimes true/never true) that all three altitudes of a triangle fall outside the triangle?
aniked [119]

never true is always 180

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Which is an example of a high-risk investment?
rewona [7]

stock in a start-up company


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Read 2 more answers
At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]
denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

f(x) = x^3-2x^2-4x+1 in the interval  [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

f(1) = 1-2-4+1 = -4\\f(0) = 1

The value

\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5

Find derivative for f

f'(x) = 3x^2-4x-4

Equate this to -5 to check mean value theorem

3x^2-4x-4=-5\\3x^2-4x+1=0\\\\(x-1)(3x-1) =0\\x= 1/3 : x = 1

We find that 1/3 lies inside the interval (0,1)

4 0
3 years ago
you pick a card at random without getting the first card back you pick a second card at random what is the probability of pickin
Keith_Richards [23]

We have to calculate the probability of picking a 4 and then a 5 without replacement.

We can express this as the product of the probabilities of two events:

• The probability of picking a 4

,

• The probability of picking a 5, given that a 4 has been retired from the deck.

We have one card in the deck out of fouor cards that is a "4".

Then, the probability of picking a "4" will be:

P(4)=\frac{1}{4}

The probability of picking a "5" will be now equal to one card (the number of 5's in the deck) divided by the number of remaining cards (3 cards):

P(5|4)=\frac{1}{3}

We then calculate the probabilities of this two events happening in sequence as:

\begin{gathered} P(4,5)=P(4)\cdot P(5|4) \\ P(4,5)=\frac{1}{4}\cdot\frac{1}{3}=\frac{1}{12} \end{gathered}

Answer: 1/12

8 0
1 year ago
Find the values for m and n that would make the following equation true.
dimaraw [331]

You would solve it in two parts.

4*n = 44     Divide by 4

4n/4 = 44/4

n = 11

=============

z^m * z^2 = z^9

When the bases are the same (on the left) the powers on the left add

m + 2

The powers on the left side of the equation are the same as the powers on the right when the bases are the same.

m + 2 = 9                 Subtract 2 from both sides.

m + 2 - 2 = 9 - 2

m = 7

=================

Answers

m = 7

n = 11

4 0
3 years ago
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