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Answer:
540 ft^2.
Step-by-step explanation:
The area of the trapezoid = h/2 (10 + 18) = 14h.
By Pythagoras the height h = √(5^2 - 4^2) = 3.
So the area of the 2 trapezoidal bases = 2 * 14*3
= 84 ft^2.
Now we calculate the area of the four lateral rectangular sides:
= 10*12 + 18*12 + 2*5*12
= 456 ft^2.
Total area = 456 + 54
= 540 ft^2.
Answer:
The answer is A. 4+y^2/2y^2
You gotta remember that
means
.
So, in this case, f(x) is [4x - 3], g(x) is [x^3 + 2x].
So that : f(x)-g(x) = [4x-3] - [x^3+ 2x] = -x^3 + 4x - 2x - 3 = -x^3 + 2x - 3