First, find out what the greatest common factor is between 2, 4, and 5.
<span>This is 20. So any number divisible by 20 is also divisible by 2, 4, and 5. </span>
<span>Now we find the list of numbers that are multiples of 20 between 67 and 113. </span>
<span>The solutions are: </span>
<span>80 and 100.</span>
You can solve this by using the system of equations.
Jan - 4.95 = 2H + 3C
Wayne - 5.45 = 3H + 2C
Use elimination.
-3(2H + 3C = 4.95)
2(3H + 2C = 5.45)
Solve. And you'll get:
-6H + (-9C) = -14.85
6H + 4C = 10.9
Cross out -6H and 6H because they cancel out. And you're left with:
-9C = -14.85
4C = 10.9
Add -9C with 4C, and -14.85 with 10.9.
-5C = -3.95
Divide each side with -5.
C = $0.79
Now to figure out what H is, just substitute the C in one of the equations with 0.79.
5.45 = 3H + 2(0.79)
5.45 = 3H + 1.58
-1.58 -1.58
3.87 = 3H
3.87/3 = 3/3(H)
1.29 = H
Finished!
Pays $94
brushes = $40
94 - 40 = 54
54 ÷ 6 = 9
each can of paint costs $9
Since Christian sets aside $60 per month for daily coffee, and McDonalds sells coffee for $ 1, and The Bean Sprout sells a cup of coffee for $3, to create an equation that represents the combinations of coffee options that allow Christian to stay in his budget and provide 2 combinations that use his entire budget, 1 combination that would be under budget, and 1 combination that would be over his budget, the following linear equation must be proposed:
M + BS = 60
2 combinations using the entire budget =
- 15 McDonalds + 15 The Bean Sprout = 15 + 45 = 60
- 30 McDonalds + 10 The Bean Sprout = 30 + 30 = 60
1 combination under budget =
- 15 McDonalds + 10 The Bean Sprout = 15 + 30 = 45
1 combination over budget =
- 30 McDonalds + 30 The Bean Sprout = 30 + 90 = 120
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Answer:
Step-by-step explanation:
A: $0.1(x) + 25(y) = x + 25
B: $0.05(x) + $40(y) = x + 40
Because they didn't give a certain amount of miles traveled, we have to go with we do know.
**this is probably wrong.