Try asking google because it’s kinda confused
<span>1. In how many games does a girl play against a boy?
A: Because there are 5 girls, each will play against 5 boys, so in total is 5*5 = 25 times.
2. </span><span>In how many games does a girl play against another girl?
A: In this case, we only need to calculate how many girl pairs are there among these 5 girls, and it become a combination problem which can solved by </span>

3.The fraction of games "B vs B" should be the number of "B vs B" (which is 10) divide the total number of the games "B vs B" & "G vs G" & "B vs G" (which is 10+10+25=45, see the analysis in 1.A and 2.A), so the fraction should be 10/45=2/9
4.One person will have to play against 9 people at the tournament, and the total number of the games is 45, so the fraction should be 9/45 = 1/5
AA Theorem: To show two triangles are similar, it is sufficient to show that two angles of one triangle are congruent (equal) to two angles of the other triangle. All three triangles have a right angle and they all share the common angle at point S.
Flagpole is 32 meters from point S: so 1.5/8 = x/32 where x is FG
cross-multiply: 32 • 1.5 = 8x
48 = 8x
x = 6 meters
building is a total of 240 meters from point S, so: 1.5/8 = x / 240 where x is BD
cross-multiply: 240 • 1.5 = 8x
360 = 8x
<span>x = 45 meters</span>
Answer:
Kindly check explanation
Step-by-step explanation:
A.)
The problem with the here is that we might have introduced bias into our sample by failing to randomize the assignment of gender. By pacing the male gender in the treatment group and females into the control group, this might spring up a spurious association in our experiment as a result of a possible confounding variable, gender. Therefore, assignment of subject shouldn't be on the basis of gender.
2.)
Using a coin toss in placing subjects into groups will give a good random assignment, however, since only ten subjects are available and of which 5 will be placed into each group, there is no certainty that there will be equal number of heads and tails during the 10 flips. Alternatively, a random selection of the name of the 10 subjects could be chosen from a raffle.
3.)
Each batch of rat might be homogenous and hence will affect our experiment and definitely our conclusion. It would be best to assign rats from each batch to all treatment groups in other to obtain a good random design