when it comes to checking if a function is even or odd, it boils down to changing the argument, namely x = -x, and if the <u>resulting function is the same as the original</u>, then is even, if the <u>resulting function is the same as the original but negative</u>, is odd, if neither, well then neither :).
anyway, that said, let's first expand it and then plug in -x,
Answer:
f⁻¹(x) = (x - 1)/8
Or
f⁻¹(x) = 1/8 x - 1/8
Step-by-step explanation:
To find the inverse of a function, switch the "x" and "y" variables, then isolate "y".
Remember <u>"f(x)" is the same thing as "y"</u>. Change from function notation to "y".
f(x) = 8x + 1
y = 8x + 1
<u>Switch the "x" and "y" variables</u>
x = 8y + 1
<u>Isolate "y"</u>. Move the "y" variable to the left for standard formatting
8y + 1 = x
8y + 1 - 1 = x - 1 Subtract 1 from both sides
8y = x - 1
Divide both sides by 8 and simplify
Inverse equation
Slope-intercept form
<u>Use function notation</u>, change "y"
Simplified
Slope-intercept form