Answer: the height of the water after the sphere is placed in
it is 33.33 cm
Step-by-step explanation:
The cylinder is called a right circular cylinder because its height make a right angle with its base. The formula for determining the volume of the cylinder is expressed as
Volume = πr^2h
Where
π is a constant whose value is 3.14
r represents the radius of the cylinder.
h represents the height of the cylinder.
From the information given,
r = 10 cm
h = height of water in the cylinder = 20 cm
Volume of water in the cylinder before the sphere was placed in it would be
V = 3.14 × 10^2 × 20 = 6280 cm^3
The formula for determining the volume of the sphere is expressed as
Volume = 4/3 πr^3
V = 4/3 × 3.14 × 10^3 = 4186.67cm^3
Total volume of the sphere and the cylinder = 6280 + 4186.67 = 10466.67 cm^2
To determine the new height of the water,
10466.67 = 3.14 × 10^2× h
h = 10466.67/314 = 33.33 cm
Answer:
Step-by-step explanation:
2
Answer:
Problem 1 = 9
Problem 2 = 260
Step-by-step explanation:
the first picture you have to use B X L X H ( base, length and height) and i got 1728 mm^3
for the second one, you have to use the formula L X H ( P+ Q/2) ( length times height times the product of the base width plus the top width divided by 2 and i got the answer of 196 m^3.
i hope this helps :)
For #4, break up what's under the radical sign into 100 * 2, and then break the n^8 into n^2*n^2*n^2*n^2 so it's easy to see how to pull out what you need to. 100 is a perfect square: 10*10, so you can pull that out, leaving the 2, and you can also pull out 4 n's, so for #4, the answer is 10n^4 sqrt2.
#5 breaks up into 9*7, with 9 being the perfect square 3*3. Break the n^9 up into n^2*n^2*n^2*n^2*n. So you can pull out the 3 and 4 of the n's, which gives you 3n^4sqrt7n
