Question

A common practice of airline companies is to sell more tickets for a particular flight than there are seats on the​ plane, because customers who buy tickets do not always show up for the flight. Suppose that the percentage of​ no-shows at flight time is 4​%. For a particular flight with 148 ​seats, a total of 150 tickets were sold. What is the probability that the airline overbooked this​ flight?

Answer 1

Answer:

0.0159

Step-by-step explanation:

Given that a common practice of airline companies is to sell more tickets for a particular flight than there are seats on the​ plane, because customers who buy tickets do not always show up for the flight.

Here if X is the no of persons that do not show up, then X is binomial as each trial is independent with p = 0.04 and n =150 (no of tickets sold)

The plane is overbooked if more than 150 show up

i.e. less than 2 do not show up

Hence  the probability that the airline overbooked this​ flight

=$P(X$