Question

Please help #22 please sos

Answer 1

Even with fractions, we still use the order of operations. The acronym to remember this is PEMDAS. First is parentheses, then exponents, multiplication/division, addition/subtraction.

The given problem is $\frac{1}{5}( 3\frac{1}{2}* \frac{4}{7} - \frac{11}{14}) + \frac{3}{28}$.
First we simplify what's in the parentheses. PEMDAS then applies in the parentheses, and since they are no further parentheses or exponents, we look at multiplication/division and multiply. First let's have all improper fractions.
$\frac{1}{5}( 3\frac{1}{2}* \frac{4}{7} - \frac{11}{14}) + \frac{3}{28} \\ = \frac{1}{5}( \frac{7}{2}* \frac{4}{7} - \frac{11}{14}) + \frac{3}{28}$.

Next multiply the fractions: numerator with numerator and denominator with denominator.
$\frac{1}{5}( \frac{7}{2}* \frac{4}{7} - \frac{11}{14}) + \frac{3}{28} \\\\ = \frac{1}{5}( \frac{28}{14} - \frac{11}{14}) + \frac{3}{28}$

Next in the parentheses is addition/subtraction.
$\frac{1}{5}( \frac{28}{14} - \frac{11}{14}) + \frac{3}{28} \\\\ = \frac{1}{5} ( \frac{17}{14}) + \frac{3}{28}$

Now apply PEMDAS again, and since there are no parentheses or exponents to simplify, we multiply.
$\frac{1}{5} ( \frac{17}{14}) + \frac{3}{28} \\\\ = \frac{17}{70} + \frac{3}{28}$

Finally find a common denominator and add.
$\frac{17}{70} + \frac{3}{28} \\\\ = \frac{34}{140} + \frac{15}{140} \\\\ = \frac{49}{140} = \frac{7}{20}$

Answer 2

1/5( 5/2 x 4/7 -11/7) + 3/28

Multiply the terms (5/2 x 4/7) in bracket then subtract it from 11/14. Result will be 10/7.

Then multiply 1/5 with 10/7. The result will be 2/7.

2/7 + 3/28 = 11/28

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