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VMariaS [17]
1 year ago
13

Where is the genetic information found in eukaryotic cells?

Mathematics
2 answers:
Sergio [31]1 year ago
7 0

Where is the genetic information found in eukaryotic cells?

NUCLEUS

Hoochie [10]1 year ago
3 0
The answer is nucleus.

Explanation:

The nucleus is like the brain of the cell, where genetic information is located and stored. It can’t be the mitochondria because that’s where ATP (energy) is generated. It can’t be the ribosomes because that is the area of informational decoding. It can’t be the lysosomes because that is the area of virus destruction.
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What is the value of z in the diagram?
lutik1710 [3]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
How would you write apples grow on trees in conditional statements?
MariettaO [177]
If it is an apple, then it grows on trees.
4 0
3 years ago
Sequences and Series precalc multiple choice, will give brainliest.
Gala2k [10]

9514 1404 393

Answer:

  False

Step-by-step explanation:

The given formula is the "explicit" formula for the sequence.

The recursive formula would be ...

  a[1] = 160

  a[n] = 1/2·a[n-1] . . . . each term expressed in as a function of previous terms

The given statement is false.

8 0
2 years ago
HElP ME!!!!!!! PLS!!!!
ra1l [238]

Answer:

Each bag will get 5 candy canes and 3 cookies.

Step-by-step explanation:

Find the divisors of both numbers

75 = 1,75 : 3,25 : 5,15 : 15,5 : 25,3 : 75,1

45 = 1,45 : 3,15 : 5,9 : 9,5 : 15,3 : 45,1

Since the largest common divisor is 15, we want to use 15.

Each bag will get 5 candy canes and 3 cookies.

4 0
3 years ago
Consider rolling two fair dice one 3-sided the other 5-sided
Ne4ueva [31]

Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

1\leq x\leq 3,\quad 1\leq y \leq 5

We have P(X=x)=\frac{1}{3} and P(Y=y)=\frac{1}{5}, because the dice are fair.

Now we use the assumption of independence to claim that

P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:

  • 2 in a unique way (1+1)
  • 3 in two possible ways (1+2, 2+1)
  • 4 in three possible ways
  • 5 in three possible ways
  • 6 in three possible ways
  • 7 in two possible ways
  • 8 in a unique way

This implies that the probabilities of the outcomes of W=X+Y are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5

8 0
3 years ago
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