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katrin [286]
3 years ago
10

Choice test you know the answer to the third question is not b or c you sure about a,d,or e. If you guess, what is the probabili

ty that u are correct
Mathematics
1 answer:
MrRissso [65]3 years ago
6 0

If there were just one question, then the probability of guessing correctly would be 1/3.

Since all the answers are independent (the answer to one question has no bearing on the answers to the others), then this is the case with each question, so the chances of guessing all answers correctly is 1/3 × 1/3 × 1/3 = 1/27. Independent choices are linked by multiplication.

To have exactly 2 answers correct, we have to think of which one is wrong: there are 3 questions and any single one could be wrong. The probability that the first question is wrong is 2/3. And we know that the probabilities of the other two being right is 1/3 each, so the probability of just the first question being wrong and the others right is 2/3 × 1/3 × 1/3 = 2/27. But this is just one of the three cases: 1/3 × 2/3 × 1/3 and 1/3 × 1/3 × 2/3 also both equal 2/27 each. So here we add the cases together: 2/27 + 2/27 + 2/27 = 6/27 = 2/9. So the answer to part (a) of your question is 2/9.

To solve (b) Consider that (b) is the same as (a) with "all answers right" added in. So you can simply add answer (a) to the chance of guessing all answers correctly.

To solve (c) it might help you to think of the equivalent problem: what is the probability of getting 0 correct plus the probability of getting 1 correct?

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\frac{5}{6}

Step-by-step explanation:

5 = 6y

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y-6=-2(x+2)

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Step-by-step explanation:

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3 years ago
Correct Answer will get BRAINLIEST!
frozen [14]

Answer:

The degree measure of ∠ACP is 112.5°

Step-by-step explanation:

The total area of the given diagram is the sum of two semicircles with arc AB and arc CB having radius R and r respectively

Where:

R = AC

r = DB

R = 2 × r

Therefore the area of the semicircles are given as follows;

For the semicircle with arc AB, we have;

Area, A₁ = π × R²/2 = π × (2×r)²/2 = 2×π×r²

For the semicircle with arc CB, we have;

Area, A₂ = π × r²/2 =  1/2×π×r²

The ratio of the two semicircles is presented in the following relation;

\dfrac{A_1}{A_2} = \dfrac{2 \cdot \pi \cdot r^2}{\dfrac{1}{2}  \cdot \pi \cdot r^2} = \dfrac{2}{\dfrac{1}{2} } = 2 \times \dfrac{2}{1}  = 4

Therefore, the area of A₁ is four times that of A₂ or A₁ =  4 × A₂

The total area of the given diagram = A₁ + A₂ = 4 × A₂ + A₂ = 5·A₂

∴ Half of the area of the diagram, A_H = 5·A₂/2 = 2.5·A₂ = 2.5 × 1/2×π×r² = 1.25×π×r²

The ratio of half of the diagram of the figure to the area of the semicircle with arc AB is found as follows;

A_H/A₁ = (1.25×π×r²)/(2×π×r²) = 5/8

Therefore, the half of the diagram of the figure given by segment PAC is equivalent to 5/8 of the semicircle with arc AB

Given that the arc AB subtends an angle of 180° at the center (angle subtended by a semicircle), the arc AP will subtend 5/8×180 = 112.5°

To verify we have;

Area of a segment of a circle is presented in the following relation;

\dfrac{\theta}{360} \times \pi  \times r^2

As segment PAC is 5/8 of a semicircle, it is therefore 5/(8×2) or 5/16 of the whole circle

Hence;

\dfrac{5}{16} \times \pi \times r^2 =  \dfrac{\theta}{360} \times \pi  \times r^2

\dfrac{5}{16} =  \dfrac{\theta}{360}

\theta \dfrac{}{} =  \dfrac{360 \times 5}{16} = 112.5 ^ {\circ}

Therefore the degree measure of ∠ACP is 112.5°.

5 0
3 years ago
Solve 5/4 - 1/3 - 1/2 subtraction subtracting fractions ​
Lerok [7]

Answer:

5/4 - 1/3 - 1/2=/2/0

Step-by-step explanation:

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