All categories

3 years ago

Add the two expressions. 8.9x−5 and −6.8x+8

Mathematics

2 answers:

Cloud [144]3 years ago

6 0

The answer is 2.1x+3

dmitriy555 [2]3 years ago

5 0

2.1x-3 I think IDK good luck

You might be interested in

Describe the transformation of f(x)=x² into the graph of the graph of the given function:

Ber [7]

Answer: f (x) + b shifts the function b units upward.

f (x) – b shifts the function b units downward.

f (x + b) shifts the function b units to the left.

f (x – b) shifts the function b units to the right.

–f (x) reflects the function in the x-axis (that is, upside-down)

hope this helps

6 0

3 years ago

Evaluate (y - 9) + (3 + x), when y = 15 and x = 5

snow_lady [41]

Hi ;-)

$y=15 \ and \ x=5\\\\(y-9)+(3+x)=(15-9)+(3+5)=6+8=\boxed{14}$

6 0

3 years ago

Read 2 more answers

Can someone help me with a basic geometry question :c

viktelen [127]

480 I’m pretty sure ( a=LxWxH)

7 0

2 years ago

The random variable x represents the number of computers that families have along with the corresponding probabilities. Find the

Elena L [17]

Answer:

The correct option is (d).

Step-by-step explanation:

The complete question is:

The random variable x represents the number of computers that families have along with the corresponding probabilities. Use the probability distribution table below to find the mean and standard deviation for the random variable x.

x : 0 1 2 3 4

p (x) : 0.49 0.05 0.32 0.07 0.07

(a) The mean is 1.39 The standard deviation is 0.80

(b) The mean is 1.39 The standard deviation is 0.64

(c)The mean is 1.18 The standard deviation is 0.64

(d) The mean is 1.18 The standard deviation is 1.30

Solution:

The formula to compute the mean is:

$\text{Mean}=\sum x\cdot p(x)$

Compute the mean as follows:

$\text{Mean}=\sum x\cdot p(x)$

$=(0\times 0.49)+(1\times 0.05)+(2\times 0.32)+(3\times 0.07)+(4\times 0.07)\\\\=0+0.05+0.64+0.21+0.28\\\\=1.18$

The mean of the random variable x is 1.18.

The formula to compute variance is:

$\text{Variance}=E(X^{2})-[E(X)]^{2}$

Compute the value of E (X²) as follows:

$E(X^{2})=\sum x^{2}\cdot p(x)$

$=(0^{2}\times 0.49)+(1^{2}\times 0.05)+(2^{2}\times 0.32)+(3^{2}\times 0.07)+(4^{2}\times 0.07)\\\\=0+0.05+1.28+0.63+1.12\\\\=3.08$

Compute the variance as follows:

$\text{Variance}=E(X^{2})-[E(X)]^{2}$

$=3.08-(1.18)^{2}\\\\=1.6876$

Then the standard deviation is:

$\text{Standard deviation}=\sqrt{\text{Variance}}$

$=\sqrt{1.6876}\\\\=1.2990766\\\\\approx 1.30$

Thus, the mean and standard deviation for the random variable x are 1.18 and 1.30 respectively.

The correct option is (d).

3 0

3 years ago

Which inequalities are true? Select the four correct answers.

enyata [817]

The right answer is the First one the second one the third one in the fifth one

5 0

3 years ago