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3 years ago

How would you find the volume of this figure? Please give an answer and explain...

Mathematics

1 answer:

Ivanshal [37]3 years ago

6 0

Step 1: Find the volumes of the squares / rectangles. Formula: V = L * H (Hint: THE BOTTOM OF THE FIGURE COUNTS AS A RECTANGLE!!!) ((Hint 2: There are 7 squares / rectangles in all!!!))

Step 2: Find the volumes of all the triangles. Formula: L * H * 1/2 (Hint: 2 triangles in all. Most likely the same size, if so, just do 1 triangle!!!)

Step 3: Once found all the volumes of the figures, add all the values and that will be the volume of the whole figure!

You are basically breaking up the figure into separate shapes!

Hopefully this helped!!! :)

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The average weight of a newborn panda is 0.2, or 2/10 pound. Between what two integers is the weight of a newborn panda?

sweet-ann [11.9K]

Answer:

$\frac{2}{10}$ lies between 0 and 1.

Step-by-step explanation:

We must have in mind that given average weight of a newborn panda is a non-integer rational number, such that lies between two integer rational number. In other words, this number must satisfy the following condition:

$n < \frac{a}{b} < n +1$ , $n, a, b \in \mathbb{N}_{O}$

$\mathbb{N}_{O} = \mathbb{N}\,\cup\,{\{0\}}$

Which is now developed mathematically to deduce a useful expression to find integers:

1) $n < \frac{a}{b} < n +1$ Given

2) $n \cdot 1 < \frac{a}{b} < n\cdot 1 + 1$ Modulative property

3) $n \cdot (b\cdot b^{-1}) < a\cdot b^{-1} < n \cdot (b\cdot b^{-1}) + b\cdot b^{-1}$ Existence of Multiplicative inverse/Definition of division.

4) $(n\cdot b)\cdot b^{-1} < a\cdot b^{-1}< [(n+1)\cdot b] \cdot b^{-1}$ Commutative, Associative and Distributive properties.

5) $n\cdot b < a < (n+1)\cdot b$ Compatibility with Multiplication/Existence of Multiplicative Inverse/Modulative Property/Result.

If we know that $a = 2$ and $b = 10$ , the following inequation is formed:

$10\cdot n < 2 < 10\cdot (n+1)$

It is quite evident to conclude that $\frac{2}{10}$ lies between 0 and 1.

6 0

3 years ago

Find the lcm for 5,8,4

mash [69]

Answer:

2⋅2⋅2⋅5=40 2 ⋅ 2 ⋅ 2 ⋅ 5 = 40

6 0

4 years ago

Read 2 more answers

Find the value of given expression <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B24%20%5Ctimes%205%20%2B%201%7D%20" id="

Orlov [11]

Answer:

your answer will be 11

Step-by-step explanation:

Thanks again!!

4 0

3 years ago

Read 2 more answers

What is the sum of the first 51 consecutive odd positive integers?

Angelina_Jolie [31]

We call:

$a_{n}$ as the set of the first 51 consecutive odd positive integers, so:

 $a_{n} = \{1, 3, 5, 7, 9...\}$

Where:
$a_{1} = 1$
$a_{2} = 3$
$a_{3} = 5$
$a_{4} = 7$
$a_{5} = 9$
and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

 $a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}$

Then:

 $a_{n} = a_{1} + (n-1)d$

So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

 $S_{k} = ( \frac{a_{1} + a_{k}}{2} ).k$

Therefore, we need to find:
 $a_{k} = a_{51}$

Given that $a_{1} = 1$ , then:

$a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1$

Thus:
$a_{k} = a_{51} = 2(51)-1 = 101$

Lastly:

$S_{51} = ( \frac{1 + 101}{2} ).51 = 2601$

4 0

3 years ago

I need an answer quick!!!!

Illusion [34]

Answer:

investment 2 $400 Simple Interest Rate

Step-by-step explanation:

5 0

3 years ago