Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.
Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.
let
be the probability that commercial cars have rear license plates and
be the probability that connected trucks have rear license plates.
Cars Trucks Total
Total 2049 334 2383
x 239 45 284
p 0.1166 0.1347 0.1191
α=0.05
Hypothesis will be :


It is a left tailed test at 0.05 significance.
Standard errors of p=
=
=
=0.0066
Test statistic Z=p difference/standard error
=(0.1166-0.1347)/0.0066
=-0.0181/0.0061
=-2.967
p value=0.001505<5%
Since p is less than 5% we reject null hypothesis.
We cannot calculate standard deviation so we cannot calculate confidence interval.
Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.
Learn more about z test at brainly.com/question/14453510
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Answer:X= 41
Step-by-step explanation:
Answer:
the answer is 8
Step-by-step explanation:
B
ASA is short for angle side angle, which you can see from angle B and angle D being congruent (all right angles are congruent), the congruent marks on line BE and line ED, and the vertical angles AEB and DEC.
D is not the answer because B and D are not in the same 'place' when naming. Silly as it is, it counts.
Hope this helps!
Answer:
The equation that would be used for the zero product property on will be (x-5)(x-10)=0
Option B is correct.
Step-by-step explanation:
We need to solve the equation 
Solving the equation:

Now, we would factorise to find value of x

So, the equation that would be used for the zero product property on will be (x-5)(x-10)=0
Option B is correct.