Answer:
The quadratic function whose graph contains these points is 
Step-by-step explanation:
We know that a quadratic function is a function of the form
. The first step is use the 3 points given to write 3 equations to find the values of the constants <em>a</em>,<em>b</em>, and <em>c</em>.
Substitute the points (0,-2), (-5,-17), and (3,-17) into the general form of a quadratic function.



We can solve these system of equations by substitution
- Substitute


- Isolate a for the first equation

- Substitute
into the second equation



The solutions to the system of equations are:
b=-2,a=-1,c=-2
So the quadratic function whose graph contains these points is

As you can corroborate with the graph of this function.
Step-by-step explanation:
normally, if we have the gradient (or slope of inclination or change rate) and a point, we start using the point-slope form :
y - y1 = a(x - x1)
with (x1, y1) being a point on the line, and a being the slope of gradient (or ... however you want to call it).
y - 1 = 2(x - 2) = 2x - 4
y + 3 = 2x
2x - y = 3
Answer:
Step-by-step explanation:
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