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sergey [27]
4 years ago
12

What is 4[2(21-17)+3]

Mathematics
1 answer:
vagabundo [1.1K]4 years ago
6 0
To solve this problem, we should understand how order of operations works. Perhaps the best way to show you this would be solving the problem with all of the work clearly labeled?

=4[2(21-17)+3]    Original Problem
=4[2(4)+3]           Solved the Parentheses
=4[8+3]                Multiplied the 2 and 4
=4[11]                   Added the 8 and 3
=44                       Multiplied the 4 and 11

An easy way to remember this is PEMDAS, which is an acronym for Parentheses, Exponents, Multiplication/Division, and Addition/Subtraction. Although it will not apply in this scenario (because we have brackets), it will come in handy for many others like this.

Using all of the information above, we can conclude that this expression equals 4.  

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Find the area of a semi-circle with radius, r = 2cm.
hoa [83]

Answer:

The answer is 2pi

Step-by-step explanation:

To find the area of a cirlce, use the equation ( pi * r^2 ) so for a semi circle, which is half, simply divide that by 2. Plug in 2 for radius and you get 4pi/2 which simplifies to 2pi.

5 0
3 years ago
The perimeter of a rectangular painting is 312 centimeters. If the width of the painting is 64 centimeters, what is its length?
Kay [80]
Perimeter= 2L + 2W
312 cm= 2L + 2(64)
312= 2L + 128
subtract 128 from both sides
184= 2L
divide both sides by 2
92 cm= L

ANSWER: The length is 92cm.

Hope this helps! :)
5 0
3 years ago
What is the estimation of 5 times 4257
melisa1 [442]
20,000 bc 5 multipled by 4000 which is about 4,257 is 20,000 which gives you a estimation
4 0
4 years ago
The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop
Anettt [7]

Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. Favorable cases for Both the laptops to be selected = _2C_2 = 1

Total number of cases = 15

Required probability is \frac{1}{15}.

b. Favorable cases for both the desktop machines selected = _4C_2=6

Total number of cases = 15

Required probability is \frac{6}{15} = \frac{2}{5}.

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

2. Both desktop:

Favorable cases = _4C_2=6

Total number of favorable cases = 8 + 6 = 14

Required probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

Total number of cases = 15

Required probability is \frac{8}{15}.

8 0
4 years ago
Solve the system of equations by substitution. What is the product of x and y from the solution? 2x + 3y = 12 5x − y = 13
Darina [25.2K]

2x + 3y = 12 (1st)

5x − y = 13 (2nd) ---> y = 5x - 13


Substitute y = 5x - 13 into (1st) equation


2x + 3(5x - 13) = 12

2x + 15x - 39 = 12

17x - 39 = 12

17x = 51

x = 3


substitute x = 7 into y = 5x - 13

y = 5x - 13

y = 5(3) - 13

y = 15 - 13

y = 2


Answer

solution x = 3 and y = 2



5 0
3 years ago
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