now, the angle of θ, can only have a "y" value that is positive on, well, y is positive at 1st and 2nd quadrants
and "x" is positive only in 1st and 4th quadrants
now, that angle θ, can only have those two fellows, "y" and "x" to be positive, only in the 1st quadrant, and also both to be negative on the 3rd quadrant.
and that those two fellows, can also be both negative in the 3rd quadrant
3/1 = 3, and -3/-1 = 3
so, the solutions can only be "3", when both "y" and "x" are the same sign, and that only occurs on the 1st and 3rd quadrants
Answer:
w = 13, 11, 12
Step-by-step explanation:
3 (15 - w)
3 (15 - 13)
3 (2)
w = 6
___
3 (15 - x)
3 (15 - 11)
3 (4)
w = 12
___
3 (15 - x)
3 (15 - 12)
3 (3)
w = 9
(hope this helps!)
The counter example: m∠ ABC = 35°, and m∠ CBD = 25°.
An angle is a figure in Euclidean geometry made up of two rays that share a common terminal and are referred to as the angle's sides and vertices, respectively. Angles created by two rays are in the plane where the rays are located. When two planes intersect each other will create an angle.
Point C is the interior of ABD.
The measure of angle ABD is 60°.
The measure of angle ABC is 40°.
The measure of angle CBD is 20°.
Now when we add the angle ABC and CBD:
∠ ABC + ∠ CBD = 40° + 20°
∠ ABC + ∠ CBD = 60°
∠ ABC + ∠ CBD = ∠ ABD
The counter-example will be:
∠ ABD = ∠ ABC + ∠ CBD
60° = 35° + 25°
Therefore,
∠ ABC = 35° and ∠ CBD = 25°
Learn more about angle here:
brainly.com/question/22323626
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I’m very excited, I get to see my brothers so that’s fun
