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Oksana_A [137]
3 years ago
6

Hey there! Can I get some help please ? Thanks!

Mathematics
1 answer:
Ivenika [448]3 years ago
5 0
The surface area is the sum of area of all faces of the shape

For the first shape:
four areas of four triangles + area of the square base

A= 4 (0.5*16*17) + (16*16) = 800 in^2

For the second shape:
area of the lateral cone + area of the circle base
A = 3.14*3* (9+64)^0.5  + 3.14 * 9 = 108.75 in^2

Hope that helps

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10e-2e-9=39 solve variable. include steps, also check your answer!
mina [271]

Answer:

e = 6

Step-by-step explanation:

10e - 2e - 9 = 39

8e - 9 = 39

8e = 48

e = 6

CHECK:

10(6) - 2(6) - 9 = 39

60 - 12 - 9 = 39

39 = 39

6 0
4 years ago
III
docker41 [41]

Answer:

8x+6=-8

x=-1,75

Step-by-step explanation:

8x+6=-8

8x=-8-6

8x÷8=-14÷8

x=1,75

3 0
3 years ago
4+6d > 28 or d-2 < -4
Pavel [41]

Answer:

Which sentence most clearly describes the genre of a story?

A. Because the climax is over quickly, there's more time to reflect.

B. Pacing is how fast the action of the story feels to the audience.

C. The novel gives more details about the character than the show

does.

D. Horror is my favorite kind of speculative fiction, after fantasy.

Step-by-step explanation:

uhhhuuuuuuuhhhhhhhhhhg

3 0
3 years ago
Problem: Report Error Two parallel chords in a circle have lengths 10 and 14, and the distance between them is 6. The chord para
charle [14.2K]

The value of \sqrt{a} = 2\sqrt{46} and a = 184

We let O be the centre, A₁ A A₂ , B₁ B B₂ represent the chords with length 10, 14 respectively.

Connecting the endpoints of the chords with the centre, we have several right triangles. However, we do not know whether the two chords are on the same side or different sides of the centre of the circle.

By the Pythagorean Theorem on Δ OBB₁,

we get x^2 + 7^2 = r^2

⇒ x = \sqrt{r^{2} - 49 }, where x is the length of the other leg. Now the length of the leg of Δ OAA₁ is either 6 + x or 6 - x depending whether or not A₁A₂, B₁B₂ are on the same side of the center of the circle:

                               (6 ± \sqrt{r^{2} - 49 } ) + 5²  =  r²

                                 12 ± 12 \sqrt{r^{2} - 49} = 0

Only the negative works here (thus the two chords are on opposite sides of the center), and solving we get x=1, r =5\sqrt{2}. The leg formed in the right triangle with the third chord is 3 - x = 2, and by the Pythagorean Theorem again,

(\frac{a}{2} )^{2}  + 2^{2}  = (5\sqrt{2} )^{2} \\

⇒ \sqrt{a} = 2\sqrt{46}

a = 184

To learn more about Pythagoras theorem from the given link

brainly.com/question/343682

#SPJ4

5 0
1 year ago
I need help with this, anyone wanna help?
Lera25 [3.4K]

Answer:

C

Step-by-step explanation:

8 0
3 years ago
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