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Georgia [21]
4 years ago
15

Taylor dropped a rubber ball from a height of 8 feet.The ball hit the ground after 1 second,bounced up to 5 feet in the next sec

ond,touched the ground after another second and bounced up to 2.5 feet after another second,at which time Taylor grabbed the ball and held it at the height for 2 more second . What is the interval where the graph is constant ?

Mathematics
1 answer:
Rzqust [24]4 years ago
3 0

Answer:

The graph is constant in the interval [4,6]

Step-by-step explanation:

We are given that,

Taylor dropped a rubber ball from a height of 8 feet.

So, at time t= 0 sec, the ball is being thrown.

Now, the next events follows as below:

1. After a second, the ball hits the ground.

2. It bounces up to 5 feet in the next second.

3. The ball again hits the ground in the next second.

4. Now, the ball again jumps up to height 2.5 feet, when Taylor holds the ball for 2 seconds more.

So, we get the figure given below, we see that,

The graph is constant in the interval [4,6].

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If p(x) = 2x2 – 4x and q(x) = x – 3, what is (pxq) (x)
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3 years ago
Solve the simultaneous equations
satela [25.4K]
I use the substitution method, but you can also use elimination and matrix

1. Solve for y in 3x+y=14
y=14-3x

2. Substitute y=14-3x into x+2y=3
-5x+28=3

3. Solve for x in -5x+28=3
x=5

4. Substitute x=5 into y=14-3x
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Have a nice day :D
7 0
3 years ago
Read 2 more answers
How can i solve this<br> (x+2)(2x+3)<br> step by step please
MrRissso [65]

Answer:

2x² + 7x + 6

Step-by-step explanation:

To solve this polynomial, you need to distribute/multiply, (x+2) with (2x+3).

You would first multiply (x) with 2x and 3. This would give you 2x² and 3x. You would then multiply 2 with 2x and 3. This would give you 4x and 6. You then add the like-terms, which are 3x and 4x, which gives you 7x. This would give you your final expression of 2x² +7x + 6.

(x+2)(2x+3)

2x²+ 3x + 4x + 6

2x² +7x + 6

6 0
3 years ago
Read 2 more answers
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