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3 years ago

I need help with this..

Mathematics

1 answer:

Misha Larkins [42]3 years ago

8 0

Answer:

a0) 2

x<0

a1) x

0≤x<3

a2) 3

x≥3

Step-by-step explanation:

As shown in the given graph

function of y is a straight line at y=2 line till x=0

hence a0:

y= 2 for x<0

Then function becomes linear line from x=0 till x=3

hence a1:

y= x for 0≤x<3

Now after that graph of function y again shift to straight line from x=3 onward with y-axis value of 3

hence a2:

y= 3 for x≥3 !

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3 years ago

Suppose f is an exponential function and:

Nastasia [14]

Answer: a) $b= p(1 + r)^1$ b) $c= p(1 + r)^n$ c) $d= p(1 + r)^m$ d) $b^n=c$

Step-by-step explanation:

Since f is an exponential function.

So, it is expressed as

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Here f is the present value

p is the initial value

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t is the time period.

(a) b represents the 1-unit growth factor for f.

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(b) c represents the n n-unit growth factor for f.

$c= p(1 + r)^n$

$d= p(1 + r)^m$

Write a formula that expresses c in terms of b.

Since

$b=p(1+r)^1\\\\So,\\\\b=p(1+r)^{n\times \frac{1}{n}}\\\\b=(p(1+r)^n)^{\frac{1}{n}}\\\\b=c^{\frac{1}{n}}\\\\b^n=c$

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

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Let f(x)= 100 / −10+ e^ −0.1x . What is f(−6) ?

bija089 [108]

The value of f(-6) is -12.2

Explanation:

Given that the function $f(x)=\frac{100}{-10+e^{-0.1\left(x\right)}}$

We need to determine the value of f(-6)

The value of f(-6) can be determined by substituting the value for $x=-6$ in the function and simplify the function.

Hence, let us substitute $x=-6$ in the function, we get,

$f(-6)=\frac{100}{-10+e^{-0.1\left(-6\right)}}$

Let us apply the rule $-\left(-a\right)=a$ , we get,

$f(-6)=\frac{100}{-10+e^{0.1\left(6\right)}}$

Multiplying the numbers, we get,

$f(-6)=\frac{100}{-10+e^{0.6}}$

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Substituting the value of $e^{0.6}=1.822$ , we get,

$f(-6)=\frac{100}{-10+1.822}$

Subtracting the denominator, we have,

$f(-6)=\frac{100}{-8.178}$

Dividing, we have,

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Rounding off to the nearest tenth, we have,

$f(-6)=-12.2$

Thus, the value of f(-6) is -12.2

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2 years ago