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Tema [17]
3 years ago
13

suppose that a certain basketball athlete earned $23,000,000 to play 80 games, each last 48 min. how much did the athlete earn p

er game, Assuming that the athlete played every min of every game how much did he earn per min, Assuming that the athlete played 2/3 of every game, how much did he earn per min, suppose that, averaged over a year, the athlete practiced or trained 35 hours for evey game and then played every min. including this training time, what was his hourly salary.

Mathematics
2 answers:
bezimeni [28]3 years ago
8 0

a. The athlete earned ​$

287,500 per game.

b. The athlete earned ​$

5989 per minute played if he played the entire game for every game.

​(Round to the nearest dollar per minute as​ needed.)

Anit [1.1K]3 years ago
5 0
He earns 23 000 000 per 80 games for 48min
Per game he earns
23000000 \div 8 0 = 782500
If he earns 782 500 per game he earns 5 989,5833 per minute

782500 \div 48 = 5989.5833
If he played 2/3 of the time he played 32min which means he earned...

782500 \div 32 = 24453.125
So he trained 35hours for a 48min match
Together that is 35.8hours

But I dont think this really matters here you just have to multiply 24453.125 with 60

And you get his hourly salary which is 1 467 187.5

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Answer:

A. The interval will be narrower if 15 men are used in the sample.

Step-by-step explanation:

Hello!

When all other things remain the same, which of the following statements about the width of the interval is correct?

A. The interval will be narrower if 15 men are used in the sample.

B. The interval will be wider if 15 men are used in the sample.

C. The interval will be narrower if 5 men are used in the sample.

D. The interval will be narrower if the level is increased to 99% confidence.

E. The interval will be wider if the level is decreased to 90% confidence.

Consider that the variable of interest "Xd: Difference between the peak power of a cyclist before training and after training" has a normal distribution. To construct the confidence interval for the population mean of the difference you have to use a pooled t-test.

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The margin of error of the interval is:

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As you can see the margin of error and the sample size (n) have an indirect relationship. This means, that when the sample size increases, the semiamplitude decreases, and when the sample size decreases, the semiamplitude increases.

↓d= t_{n-1;1-\alpha /2} * (Sd/↑n)

↑d= t_{n-1;1-\alpha /2} * (Sd/↓n)

Correct option: A. The interval will be narrower if 15 men are used in the sample.

2) The confidence level has a direct relationship with the semiamplitude of the interval, this means that when the confidence level increases, so do the semiamplitude, and if the level decreases, so do the semiamplitude:

↓d= ↓t_{n-1;1-\alpha /2} * (Sd/n)

↑d= ↑t_{n-1;1-\alpha /2} * (Sd/n)

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Answer:

Step-by-step explanation:

no of days                                                   no of men

30                                                                         20

24                                                                             20

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