<u>f(x) = x + 3</u>
f(2) = 2 + 3
f(2) = 5
f(4) = 4 + 5
f(4) = 9
f(6) = 6 + 5
f(6) = 11
{(2, 5), (4, 9), (6, 11)}
Answer:
the answer is 5
Step-by-step explanation:
Answer:4
Step-by-step explanation:
log₂[log₂(√4x)] = 1
log₂2 =1
So we replace our 1 with log₂2
log₂[log₂(√4x)] = log₂2
log₂ on bothside will cancel each other.
We will be left with;
[log₂(√4x)] = 2
log = power of exponential
√4x = 2²
√4x = 4
Square bothside
(√4x)² = 4²
4X = 16
Divide bothside by 4
4x/4 = 16/4
x = 4
Use the identity
sec^2x = 1 + tan^2 x
- so sec x = sqrt(1 + tan^2 x) then:-
tan x + sqrt( 1 + tan^2 x) = 1
sqrt ( 1 + tan^2 x) = 1 - tan x
1 + tan^2 x = 1 + tan^2x - 2 tan x
0 = -2 tanx
tan x = 0
x = 0, π
π is an extraneous root because sec 180 = -1
So the answer is 0 degrees
