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Delvig [45]
2 years ago
9

(9 + 3) x 8 = 19 x 8) + (3 *__)

Mathematics
2 answers:
Taya2010 [7]2 years ago
8 0

Answer:

x = 8

Step-by-step explanation:

(9 + 3) x 8 = (9 x 8) + (3 x x)

(9 + 3) x 8 = (9 x 8) + (3 x 8) = True

Molodets [167]2 years ago
5 0

Answer:

HOPE IT HELPS

Step-by-step explanation:

(9 + 3) x 8 = (9 x 8) + (3 × <u>8</u>)

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Can someone help please!! i’ll give brainliest
vladimir1956 [14]

Answer: f (-2 -5) f (1 4)

Step-by-step explanation:

8 0
3 years ago
What is the solution set of the equation?
mihalych1998 [28]
It would be 12 (B)
thats i beleive the answer

4 0
3 years ago
In circle O, RT and SU are diameters.
nataly862011 [7]

In circle O, RT and SU are diameters. mArc R V = mArc V U = 64°. Thus, option C is correct.

Given that:

mArc R V = mArc V U,

Angle S O R = 13 x degrees

Angle T O U = 15 x - 8 degrees

<h3>How to calculate the angle TOU ?</h3>

∠SOR = ∠TOU  (Vertically opposite angles are equal).

Therefore:

13 x = 15x - 8

Subtracting 13x from both sides

13x - 13x = 15x - 8 - 13x

0 = 15x - 13x - 8

2x - 8 = 0

Adding 8 to both sides:

2x - 8 + 8 = 0 + 8

2x = 8

2x/2 = 8/2  

x = 4

∠SOR = 13x

= 13(4)

= 52°

∠TOU = 15x - 8

= 15(4) - 8

= 60 - 8

= 52°

Let a = mArc R V = mArc V U

Therefore:

mArc R V + mArc V U + ∠TOU = 180 (sum of angles on a straight line)

Substituting:

a + a + 52 = 180

2a = 180-52

2a = 128

a = 128/2

a= 64°

mArc R V = mArc V U = 64°

In circle O, RT and SU are diameters. mArc R V = mArc V U = 64°. Thus, option C is correct.

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

6 0
2 years ago
Please helpppp meee I will give you brainlist
Mila [183]

Answer:

You did not attach any files. please make sure to attach files when you have questions like this. Have a good day.

Step-by-step explanation:

<em>The world is filled with nice people. If you can't find one, be one.</em>

<em>-mhanifasbiggestfan</em>

7 0
3 years ago
QUESTION 1
Kitty [74]

It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.

Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is

<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)

The cosine of the angle between the vectors can be obtained from the dot product identity,

<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>)   ==>   cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)

so that

<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)

For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is

<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))

==>   <em>W</em> ≈ 5.12 J

(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).

3 0
3 years ago
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