Answer:
The WIP limit is 0.50 days.
Step-by-step explanation:
The Computation of WIP limits:
to begin with, it is required to compute the process and procedure efficiency which will be computed as follows:
Value Added Time = 12 days (arriving time)
Non-Value-Added Time = 12 days (departure time)
Efficiency = Value Added / (Value Added + Non-Value Added)
= 12 / (12+12)
= 12 / 24
= 0.50 or 50%
the most obligatory throughput time will be 0.25 days to realize the profits
WIP limit = Throughput time / Efficiency
= 0.25 / 50%
= 0.50 days.
The WIP limit is 0.50 days.
Answer:
There's no context for a conclusion.
Step-by-step explanation:
Comment when you've edited the question.
Answer:
a) = 4.5
b) = 3.3
Step-by-step explanation:
Before solving our problems given to us let us under stand the rule of cube roots
It says
-----(A)
Also
---(B)
Now let us see each part one by one
a) we have
![\sqrt[3]{64} + \sqrt[3]{0.027} + \sqrt[3]{0.008}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%2B%20%5Csqrt%5B3%5D%7B0.027%7D%20%2B%20%5Csqrt%5B3%5D%7B0.008%7D)
Now 64 = 4 x 4 x 4
0.027 = 0.3 x 0.3 x 0.3
0.008 = 0.2 x 0.2 x 0.2
substituting these values
![\sqrt[3]{4 \times 4 \times 4} + \sqrt[3]{0.3 \times 0.3 \times 0.3} + \sqrt[3]{0.2 \times 0.2 \times 0.2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%20%5Ctimes%204%20%5Ctimes%204%7D%20%2B%20%5Csqrt%5B3%5D%7B0.3%20%5Ctimes%200.3%20%5Ctimes%200.3%7D%20%2B%20%5Csqrt%5B3%5D%7B0.2%20%5Ctimes%200.2%20%5Ctimes%200.2%7D)
Applying Rule A in above


4.5
b) we have ![\sqrt[3]{0.3 \times 0.3 \times 0.3 \times 11 \times 11 \times 11}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.3%20%5Ctimes%200.3%20%5Ctimes%200.3%20%5Ctimes%2011%20%5Ctimes%2011%20%5Ctimes%2011%7D)
Applying the B rule in this

3.3
Answer:
Im sorry! idk the answer but if you have a phone, there is this app called photo math, or ask you mom or dad for help.
Step-by-step explanation: