a is height p is perimeter
Answer:
0.8 cm
Step-by-step explanation:
The formula for MAD is attached in the picture.
x_i are the values (data)
x bar is the mean
n is the number of numbers (data)
For figuring out MAD, basically, <em>we subtract the mean from each of the values respectively and take the absolute value and SUM for all of the numbers in the data set. Then we divide by n, the number of numbers.</em>
<em />
Let's do this:
MAD = 
MAD is 0.8
Answer:
(c, d) = (25, 35)
Step-by-step explanation:
Multiply the first equation by 2.5 and subtract the second one:
2.5(c +d) -(2.5c +1.75d) = 2.5(60) -(123.75)
0.75d = 26.25 . . . . . . . . . simplify
26.25/0.75 = d = 35 . . . . divide by the coefficient of d
60 -d = c = 25 . . . . . . . . . use the first equation to find c
(c, d) = (25, 35)
<u>Given</u>:
If you are dealt 4 cards from a shuffled deck of 52 cards.
We need to determine the probability of getting two queens and two kings.
<u>Probability of getting two queens and two kings:</u>
The number of ways of getting two queens is 
The number of ways of getting two kings is 
Total number of cases is 
The probability of getting two queens and two kings is given by

Substituting the values, we get;

Simplifying, we get;



Thus, the probability of getting two queens and two kings is 0.000133
Answer:
See explanation
Step-by-step explanation:
If a quadratic trinomial has a leading coefficient of 1 and a positive constant, then it is very easy to factor.
You just have to look for two factors of the constant term that add up to the coefficient of x( the middle term).
Then you write as factors.
For instance;

To factors of 6 that add up to 5 are 2 and 3.
Therefore the factorization is:
