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3 years ago

7

Could someone help me with these questions. I know I have some answers for them but I got them wrong so I need help to get the r

ight answet

2 answers:

Salsk061 [2.6K]3 years ago

7 0

Using external angle theorme

3x-20=110+x
2x-20=110
2x=130
x=65

Vera_Pavlovna [14]3 years ago

6 0

I am not quite sure but I hope it helps!

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Rewrite the following in the form log(c).<br> log(10) - log(2)

serg [7]

Answer:

log 5

Step-by-step explanation:

We can rewrite this by using a property of logs

log a - log b = log (a/b)

log(10) - log(2)

log(10/2)

log 5

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3 years ago

The first element in an arithmetic sequence is 2. Its twenty second is 14. Find the value of n so that a(n)=6

Aleks04 [339]

Answer:

<h2>n = 8</h2>

Step-by-step explanation:

Given the nth term of an arithmetic sequence to be Tn = a+(n-1)d

a = first term of the sequence

n = number of terms

d = common difference.

Given the first element a = 2 and 22nd to be 14

T22 = a+(22-1)d = 14

a+21d = 14

Substtuting a = 2 into the equation to get d

2+21d = 14

21d = 12

d = 12/21

d = 4/7

The nth term of the sequence given a = 2 and d = 4/7 will be expressed as;

Tn = 2+(n-1)4/7

Given Tn = 6

6 = 2+(n-1)4/7

6 = 2+4/7 n - 4/7

6-2+4/7 = 4/7 n

32/7=4/7 n

32 = 4n

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3 years ago

Find the number of distinct triangles with c=3, b=5 and B=85 degrees

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3 years ago

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Which of these expressions CANNOT be simplified by combining like terms?

densk [106]

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$5ab^{3}+3a^{2}b^{2}+a^{3}b -10$ cannot be simplified any more by combining like terms.

By distributing the 2b into the parentheses, you can simplify the expression:
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Here you can just add:
$5a^{3}b^{3}+3a^{2}b^{2}+a^{3}b^{3}-10ab\\
6a^{3}b^{3}+3a^{2}b^{2}-10ab$

Thus, the only expression that cannot simplify any more using adding like terms is the second, $5ab^{3}+3a^{2}b^{2}+a^{3}b -10$ .

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3 years ago

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What is the probability that you and your friend are both chosen?

WINSTONCH [101]

Answer: $\frac{2}{35}$

Step-by-step explanation:

Given: The total number of ways of to choose 3 contestants out of 7 (including me and my friend)=35..................> Total outcomes.

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Then the probability that me and my friend are both chosen = $\frac{\text{favorable outcomes }}{\text{Total outcomes}}$

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3 years ago

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