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Luden [163]
3 years ago
6

Explaining How to Compare Water Levels Ericka decided to compare her observation to the average annual trend, which shows the wa

ter rising 1.8 mm/year. Remember, she used 6.2 years as her time period. Explain how she would calculate the difference between how much water levels rose on average and how much the water level fell in the part of the river she observed.

Mathematics
2 answers:
Sladkaya [172]3 years ago
7 0

Answer: She would multiply the rate by the years to find the average rise in water levels, or 1.8 times 6.2 = 11.16. To find the difference between the water levels, she would subtract -13.64 from 11.16.

Step-by-step explanation:

Andrew [12]3 years ago
3 0

Step-by-step explanation:

Below is an attachment containing the solution

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jeka57 [31]

Part A - The average value of v(t) over the interval  (0, π/2) is 6/π

Part B -  The displacement of the yo-yo from time t = 0 to time t = π is 0 m

Part C - The total distance the yo-yo travels from time t = 0 to time t = π is 6 m.

<h3>Part A: Find the average value of v(t) on the interval (0, π/2)</h3>

The average value of a function f(t) over the interval (a,b) is

f(t)_{avg}  = \frac{1}{b - a} \int\limits^b_a {f(t)} \, dx

So, since  velocity at time t is given by v(t) = 3cos(t) for time t ≥ 0. Its average value over the interval  (0, π/2) is given by

v(t)_{avg}  = \frac{1}{\frac{\pi }{2}  - 0} \int\limits^{\frac{\pi }{2} }_0 {v(t)} \, dt

Since v(t) = 3cost, we have

v(t)_{avg}  = \frac{1}{\frac{\pi }{2}  - 0} \int\limits^{\frac{\pi }{2} }_0 {3cos(t)} \, dt\\= \frac{3}{\frac{\pi }{2}} \int\limits^{\frac{\pi }{2} }_0 {cos(t)} \, dt\\= \frac{6}{{\pi}}  [{sin(t)}]^{\frac{\pi }{2} }_{0} \\= \frac{6}{{\pi}}  [{sin(\frac{\pi }{2})} - sin0]\\ = \frac{6}{{\pi}}  [1 - 0]\\ = \frac{6}{{\pi}}  [1]\\ = \frac{6}{{\pi}}

So, the average value of v(t) over the interval  (0, π/2) is 6/π

<h3>Part B: What is the displacement of the yo-yo from time t = 0 to time t = π?</h3>

To find the displacement of the yo-yo, we need to find its position.

So, its position x = ∫v(t)dt

= ∫3cos(t)dt

= 3∫cos(t)dt

= 3sint + C

Given that at t = 0, x = 3. so

x = 3sint + C

3 = 3sin0 + C

3 = 0 + C

C = 3

So, x(t) = 3sint + 3

So, its displacement from time t = 0 to time t = π is

Δx = x(π) - x(0)

= 3sinπ + 3 - (3sin0 + 3)

= 3 × 0 + 3 - 0 - 3

= 0 + 3 - 3

= 0 + 0

= 0 m

So, the displacement of the yo-yo from time t = 0 to time t = π is 0 m

<h3>Part C: Find the total distance the yo-yo travels from time t = 0 to time t = π. (10 points)</h3>

The total distance the yo-yo travels from time t = 0 to time t = π is given by

x(t)  = \int\limits^{\pi}_0 {v(t)} \, dt\\=  \int\limits^{\pi }_0 {3cos(t)} \, dt\\= 3 \int\limits^{\pi }_0 {cos(t)} \, dt\\  = 3 \int\limits^{\frac{\pi }{2} }_0 {cos(t)} \, dt  + 3\int\limits^{\pi }_{\frac{\pi }{2}} {cos(t)} \, dt\\= 3 \times 2\int\limits^{\frac{\pi }{2} }_0 {cos(t)} \, dt\\= 6 [{sin(t)}]^{\frac{\pi }{2}  }_{0} \\= 6[{sin\frac{\pi }{2}  - sin0]\\\\= 6[1 - 0]\\= 6(1)\\= 6

So, the total distance the yo-yo travels from time t = 0 to time t = π is 6 m.

Learn more about average value of a function here:

brainly.com/question/15870615

#SPJ1

4 0
1 year ago
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