What is 3 to the square root of 1089

Mathematics

1 answer:

Nana76 [90]1 year ago

8 0

3 to square root of 1089 is

5.5590606e+15

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10 Pts <br> Multiplying fractions:<br><br> 5 1 <br> — x — = <br> 6 2

Flauer [41]

Multiply the numerators together. Multiply the denominators together. Then reduce if necessary.

$\dfrac{first~numerator}{first~denominator} \times \dfrac{second~numerator}{second~denominator} = \dfrac{(first~numerator)\times(second~numerator)}{(first~denominator)\times(second~denominator)}$

$\dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{a \times c}{b \times d}$

$\dfrac{5}{6} \times \dfrac{1}{2} = \dfrac{5 \times 1}{6 \times 2} = \dfrac{5}{12}$

6 0

3 years ago

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Line segment YV of rectangle YVWX measures 24 units.

oksian1 [2.3K]

Answer: $YX=13.85\ units$

Step-by-step explanation:

<h3> The complete exercise is: "Line segment YV of rectangle YVWX measures 24 units. What is the length of line segment YX?"</h3><h3> The missing figure is attached.</h3>

Since the figure is a rectangle, you know that:

$WV=YX\\\\YV=XW=24$

Notice that the segment YV divides the rectangle into two equal Right triangles.

Knowing the above, you can use the following Trigonometric Identity:

$tan\alpha =\frac{opposite}{adjacent}$

You can identify that:

$\alpha =30\°\\\\opposite=YX\\\\adjacent=YV=24$

Therefore, in order to find the length of the segment YX, you must substitute values into $tan\alpha =\frac{opposite}{adjacent}$ and then you must solve for YX.

You get that this is:

$tan(30\°)=\frac{YX}{24}\\\\(24)(tan(30\°))=YX\\\\YX=13.85$