Question

18 PTS! From the equation below, identify the slope and a point on the line. y−3=−2(x+1)

Answer 1

ANSWER:  

The slope of the given equation is -2 and a point on the given line is (-1, 3)

SOLUTION:

Given, linear equation in two variables is y – 3 = -2(x + 1) ----- eqn (1)

We need to find the slope of the given equation and a point through which the given line passes.

Given equation is in the form of point slope form  .i.e $\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)$ --- eqn 2

where,"m" is the slope of the line

$\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)$ is point on that line.

Now, by comparing (1) and (2)

m = -2

$x_{1}=-1$

$y_{1}=3$

so, the slope of the given equation is -2  and a point on the given line is (-1, 3)