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nasty-shy [4]
3 years ago
6

Jock decided to swim 10 km up Bega River. He swam 2 km every hour, then floated on his back for 10 minutes. Each time he floated

, the current dragged him back 1 km. How long did it take Jock to complete the swim?
Mathematics
1 answer:
lara31 [8.8K]3 years ago
3 0
Effectively Jock gets 1km further every round of 1:10 hrs. After 8 rounds he has reached 8km (after just having floated back from 9 to 8). The next round he completes the journey without floating.

So total 9 hours of swim and 8*10 minutes of float, that's 10 hours and 20 minutes.
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Answer:

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Step-by-step explanation:

8 0
3 years ago
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Nonamiya [84]
\bf \lim\limits_{x\to \infty}~\cfrac{2x}{3x^2+5}\implies \cfrac{\lim\limits_{x\to \infty}~2x}{\lim\limits_{x\to \infty}~3x^2+5}

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as the denominator increases faster, since as the lingo goes, "reaches the limit faster than the numerator", the fraction becomes ever smaller an smaller ever going towards 0.

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\bf \lim\limits_{x\to \infty}~\cfrac{2x}{3x^2+5}\stackrel{LH}{\implies }\lim\limits_{x\to \infty}~\cfrac{2}{6x}

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5 0
3 years ago
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Step-by-step explanation:

Hey, there!!

Here, one point is A(10,8) and P(8,5) is the midpoint.

Let B(x,y) be the another end point.

Now,

Using midpoint formulae,

p(x.y) =  \frac{x1 + x2}{2} . \frac{y1 + y2}{2}

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Since they are equal,equating with their corresponding elements we get,

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or, 16 = 10 + x

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Therefore, x = 6

Now,

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Therefore, The coordinates of another point are B(6,2)

<em><u>Hope it helps</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Answer:

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