The clock face is divided into sixty equal parts, each minute. The minute hand is located on the 20 minute mark at 6:20, the hour hand located between the 30 minute mark and the 35 minute mark. When the minute hand goes all sixty minutes, the hour hand only moves five, so to figure out the location of the hour hand, we look at how much the hour has progressed, in this case 20 minutes, or one third of the hour. So the minute hand has moved one third of the way through the hour, so has the hour hand moved one third of the way through the five minutes, or, five thirds of a minute, which is one and two thirds minute, one minute forty seconds. That puts the hour hand at thirty minutes plus one minute and forty seconds—at 31min 40sec—which is 11min 40sec farther than the minute hand.

Step-by-step explanation:

4 0

2 years ago

Which of the following is the quotient of the rational expressions shown

Natali5045456 [20]

Answer:

2x^3/x+5/x-5/ 3x-1

2x^3/ 3x-1

Step-by-step explanation:

we can cut plus and minus sign

3 0

3 years ago

Read 2 more answers

A mobile company charges a fixed rate of x cents per minute for the first 120 minutes of talk time and another rate of y cents p

patriot [66]

Answer:

$21.2

Step-by-step explanation:

From the problem given, we express them as algebra so that we can easily solve;

the total charge on a call greater than 120min is given as;

120x + y(n - 120) = total cost of call

where n is the number of minutes which is greater than 120;

Ethan paid $26.80 for 175 mins

n = 175min here;

120x + y(175 - 120) = 26.80

120x + 55y = 26.80 ----- (I)

$32.40 for 210 minutes

n = 210min

120x + y(210 - 120) = 32.4

120x + 90y = 32.4 ----- (II)

Now let us solve both equations for y and x;

120x + 55y = 26.80 ----- (I)

120x + 90y = 32.4 ----- (II)

subtract the two equations;

90y - 55y = 32.4 - 26.8

35y = 5.6

y = $\frac{5.6}{35}$ = 0.16cents

then x;

120x = 26.8 - 55y from equation I

120x = 26.8 - 55(0.16)

120x = 18

x = $\frac{18}{120}$ = 0.15cents

Find the cost of 140min of talk time;

n =140min;

= 120(0.15) + 0.16(140 - 120)

= 18 + 0.16(20)

= 18 + 3.2

= $21.2

4 0

3 years ago

Help!!!!Find the slope of the line on the graph.

artcher [175]

Answer:

$m=\frac{-1}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point (0, -4)

Point (-8, 0)

Step 2: Find slope m

Substitute: $m=\frac{0+4}{-8-0}$
Add/Subtract: $m=\frac{4}{-8}$
Simplify: $m=\frac{-1}{2}$

8 0

3 years ago