Answer:
In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -
one side of triangle = 6/2 =3 (half of the diagonal)
other side = 8/2 = 4
a^2 + b^2 = c2
3 ^2 + 4^2 = c^2
9+16 = c^2
c^2=25
c = = 5
the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !
The function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)
<h3>What is a function?</h3>It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have:
The graph of a function f(x) passes through the following points: (0,2), (1, 0), (-1,0)
Let
f(x) = ax² + bx + c
Plug x = 0, and y = 2
c = 2 ...(1)
Plug x = 1 and y = 0
a + b + c = 0 ..(2)
Plug x = -1 and y = 0
a - b + c = 0 ...(3)
After solving (1), (2), and (3)
a = -2
b = 0
c = 2
f(x) = -2x² + 2
Thus, the function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)
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