Answer:
D and F
Step-by-step explanation:
can be rewritten as
.
From there you can use the quadratic formula
(ignore the A, I can‘t seem to remove it), where a=1, b=4, and c=-8.

Then you get 
Then you get 
So 
Which means
or
which are choices D and F.
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
P = 2x^3 - 4x^2 - 16x
Step-by-step explanation:
Only 1 step: divide both sides by x
Given:
Point D is the centroid of Triangle ABC and DE = 9.
To find:
The measures of CD and CE.
Solution:
We know that, centroid is the intersection of medians and it divides each median in 2:1.
In triangle ABC, CE is a meaning and centroid D divided CE in 2:1. So,
Let the measures of CD and DE are 2x and x respectively.
DE = 9 (Given)

Now,



And,



Therefore, the measure of CD is 18 units and the measure of CE is 27 units.
The answer is x^6(2X^6-3)(4X^12+6X^6+9)