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Alenkinab [10]
2 years ago
11

Which graph represents the function h(x) = 1x1 + 0.5?

Mathematics
2 answers:
slamgirl [31]2 years ago
6 0

Answer:Top right

Step-by-step explanation:

Because they are all the same V shape, we look to the slope for the answer.

Because the Y-intercept in this equation is 0.5, we look for the graph in which it is centered and at 0.5

That would be the top right.

fredd [130]2 years ago
4 0

Answer:

the third one is the one thats correct

Step-by-step explanation:

Because they are all the same, you can't figure it out from the parent function, |x|. As a result, you must calculate it using the y-intercept. The y-intercept of a function is almost always the function's constant.

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The ABC Toy Company is creating two similar pieces for board game, as shown below. Find the value of y that makes the two pieces
Ira Lisetskai [31]
A shape that is similar to another shape will be enlarged by a scale factor. 
Each corresponding sides should give the same scale factor

Side GI corresponds to side JL
Side GH corresponds to side JK
Side HI corresponds to side KL

The correspond sides whose length are given is 
GH = 4 and JK = 8

Side JK is twice longer than GH

All the other sides of triangle JKL are twice longer than triangle GHI, so we want that the side JL to be twice of the sides GI

Side GI = 6
Side JL = 6 × 2 = 12

Answer: y = 12


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3 years ago
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2 years ago
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3 years ago
If 2/3 of a certain number is subtracted from twice the number, the result is 20. Find the number.​
sleet_krkn [62]

Let x be the number.

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3 years ago
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Sam wanted to buy candy for all of his friends to share at lunch. One pound of chocolates cost $6.95, but Sim only needs 0.6 of
OLga [1]

Answer:

The answer to your question is cost of 0.6 pound of candy $4.17

Step-by-step explanation:

Data

1 pound of candy = $6.95

only 0.6 pounds

final cost = ?

Process

1.- Use proportions to find the cost of 0.6 pounds of candy

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2.- Use cross multiplication

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3.- Simplification and result

                 x = $ 4.17          

5 0
3 years ago
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