Answer:
π(2ft)2(10ft) + one over three π(2ft)2(13ft − 10ft)
Explanation:
Given the following:
Diameter of silo = 4ft
Length of silo (h)= 13ft
Length of cylindrical part (h)= 10ft
Therefore, length of conical part(h) = (13 - 10) = 3ft
Radius(r) = diameter/2 = 4/2 = 2
The volume of a cylinder :
πr^2h
π(2ft)^210ft = π4ft10ft
The volume of cone :
1/3πr^2h
1/3π(2ft)^23ft = 1/3π4ft3ft
Therefore, the total volume of grains that can be stored in the silo equals
The volume of cylinder + volume of a cone
π(2ft)^210ft + 1/3π(2ft)^2(13 - 10)ft