Answer:
Factor this polynomial:
F(x)=x^3-x^2-4x+4
Try to find the rational roots. If p/q is a root (p and q having no factors in common), then p must divide 4 and q must divide 1 (the coefficient of x^3).
The rational roots can thuis be +/1, +/2 and +/4. If you insert these values you find that the roots are at
x = 1, x = 2 and x = -2. This means that
x^3-x^2-4x+4 = A(x - 1)(x - 2)(x + 2)
A = 1, as you can see from equation the coefficient of x^3 on both sides.
Typo:
The rational roots can be
+/-1, +/-2 and +/-4
Step-by-step explanation:
The answer is A.
D= 6<=x<=11
I’m not sure if the 2 is counted in the equation or not
Since x=4, substitute it for x in the other equation
4+3y=29
3y=25
Y=8.333333333
2(4)+3y=29
8+3y=29
3y=37
y=12.33333333
Answer:
I got
which is 46.76537.... in decimal form.
Step-by-step explanation: