All categories

3 years ago

I have a piece of material 17 ft i only need 5/8 of it how much is that

Mathematics

2 answers:

vladimir2022 [97]3 years ago

8 0

17 ft* (5/8)= 10.625 ft

The final answer is 10.625 ft~

lukranit [14]3 years ago

3 0

5/8 of 17 is 10.625!

You might be interested in

Carson can choose one vehicle (car or truck), one color (blue, red, or silver), and one type of transmission (standard or automa

77julia77 [94]

Answer:

12 possible outcomes

Step-by-step explanation:

Choosing 1 vehicle from 2 = 2C1 = 2

Choosing 1 color from 3 = 3C1 = 3

Choosing 1 type from 2 = 2C1 = 2

Number of possible outcomes :

2C1 * 3C1 * 2C1

2 * 3 * 2

= 12 different possible outcomes

5 0

3 years ago

Let X and Y be discrete random variables. Let E[X] and var[X] be the expected value and variance, respectively, of a random vari

Ulleksa [173]

Answer:

(a) $E[X+Y]=E[X]+E[Y]$

(b) $Var(X+Y)=Var(X)+Var(Y)$

Step-by-step explanation:

Let X and Y be discrete random variables and E(X) and Var(X) are the Expected Values and Variance of X respectively.

(a)We want to show that E[X + Y ] = E[X] + E[Y ].

When we have two random variables instead of one, we consider their joint distribution function.

For a function f(X,Y) of discrete variables X and Y, we can define

$E[f(X,Y)]=\sum_{x,y}f(x,y)\cdot P(X=x, Y=y).$

Since f(X,Y)=X+Y

$E[X+Y]=\sum_{x,y}(x+y)P(X=x,Y=y)\\=\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y).$

Let us look at the first of these sums.

$\sum_{x,y}xP(X=x,Y=y)\\=\sum_{x}x\sum_{y}P(X=x,Y=y)\\\text{Taking Marginal distribution of x}\\=\sum_{x}xP(X=x)=E[X].$

Similarly,

$\sum_{x,y}yP(X=x,Y=y)\\=\sum_{y}y\sum_{x}P(X=x,Y=y)\\\text{Taking Marginal distribution of y}\\=\sum_{y}yP(Y=y)=E[Y].$

Combining these two gives the formula:

$\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y) =E(X)+E(Y)$

Therefore:

$E[X+Y]=E[X]+E[Y] \text{ as required.}$

(b)We want to show that if X and Y are independent random variables, then:

$Var(X+Y)=Var(X)+Var(Y)$

By definition of Variance, we have that:

$Var(X+Y)=E(X+Y-E[X+Y]^2)$

$=E[(X-\mu_X +Y- \mu_Y)^2]\\=E[(X-\mu_X)^2 +(Y- \mu_Y)^2+2(X-\mu_X)(Y- \mu_Y)]\\$Since we have shown that expectation is linear$\\=E(X-\mu_X)^2 +E(Y- \mu_Y)^2+2E(X-\mu_X)(Y- \mu_Y)]\\=E[(X-E(X)]^2 +E[Y- E(Y)]^2+2Cov (X,Y)$

Since X and Y are independent, Cov(X,Y)=0

$=Var(X)+Var(Y)$

Therefore as required:

$Var(X+Y)=Var(X)+Var(Y)$

7 0

3 years ago

What is the answer of reciprocal of 1/7

serg [7]

7/1, I think that’s right

3 0

3 years ago

Read 2 more answers

Lerok [7]

3. Here we use the formula

$A = P ( 1 + \frac{r}{n} )^ {nt}$

And we have the following values given

$P = $23400, r = 3%=0.03,n =2, t=10 years$

So we will get

$A = 23400(1+ \frac{0.03}{2} )^{2*10}
\\
A = 23400( \frac{2.03}{2} )^{20} = $31516.52$

Question 4.

In this question , we have

$P = $2310, R = 3.5% = 0.035 ,
\\
Number \ of \ days \ from \ april \12 to July \ 5 = 30+31+23 = 84 days$

$A = 2310(1+ \frac{0.035}{365})^{84} = $2328.68$

Interest is the difference of amount and principal, that is

$I = 2328.68-2310 = $18.68$

5 0

3 years ago

What is the solution to the system? x + y = 4 x+y=1

Lelechka [254]

Given :

x + y = 4
x + y = 1

To Find :

The value of x and y.

Answer :

x + y = 4 ....[Equation (i)]
x + y = 1......[Equation (ii)]

Adding eqⁿ (ii) and eqⁿ (i) we get :

→ x + y + x - y = 4 + 1

→ 2x = 5

→ x = 5/2

→ x = 2.5

Now, put the value of x = 5/2 in eqⁿ (i) we get :

→ x + y = 4

→ 5/2 + y = 4

→ y = 4 - 5/2

→ y = 1.5

4 0

3 years ago