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EastWind [94]
4 years ago
6

The area of the octagon below is 10,391.9 square millimeters. An octagon has an apothem of 56 millimeters and an area of 10,391.

90 square millimeters. What is the approximate perimeter of the octagon? Round to the nearest whole number. mm What is the approximate length of one side of the octagon? Round to the nearest whole number. mm
Mathematics
2 answers:
pentagon [3]4 years ago
8 0

Answer: 371 mm and 46 mm

Step-by-step explanation: I got it right on edge

VladimirAG [237]4 years ago
3 0

Answer:

371 & 46

Step-by-step explanation:

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
almond37 [142]

Answer:  742

<u>Step-by-step explanation:</u>

The given sequence {27, 31, 35, ... } provides the following information:

  • the first term (a₁) = 27
  • the difference (d) = 4

We can use the information above to find the explicit rule of the sequence:

a_n=a_1+d(n-1)\\.\quad =27+4(n-1)\\.\quad =27+4n-4\\.\quad =23+4n

We can use the explicit rule to find the 14th term (a₁₄)

a_n=23+4n\\a_{14}=23+4(14)\\.\quad =23+56\\.\quad =79

Next, we can input the first and last term of the sequence into the Sum formula:

S_n=\dfrac{a_1+a_n}{2}\times n\\\\S_{14}=\dfrac{a_1+a_{14}}{2}\times 14\\\\.\quad =\dfrac{27+79}{2}\times 14\\\\.\quad =\dfrac{106}{2}\times 14\\\\.\quad =53\times 14\\\\.\quad =742

3 0
3 years ago
Read 2 more answers
Find the missing number.<br> 15:12 = 35: ?
Vitek1552 [10]

Step-by-step explanation:

35:28

Hope it helps......

7 0
3 years ago
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The hyperbolas is The point halfway between its two vertices
vagabundo [1.1K]
A hyperbola is like having two asymptotic parabolas facing opposite to each other. The point halfway between the vertices of the two parabolas is the hyperbola's center point.

Thank you for posting your question here in Brainly. I hope I was able to help you. Have a good day.
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What is the equation of the line that passes through (-9,12) and is perpendicular to the line whose equation is y=1/3x 6?
tigry1 [53]
Y = 1/3x ? 6....slope here is 1/3. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So our perpendicular line will have a slope of -3 (see how I flipped 1/3 and changed the sign)

y = mx + b
slope(m) = -3
(-9,12)...x = -9 and y = 12
now we sub and find b, the y int
12 = -3(-9) + b
12 = 27 + b
12 - 27 = b
-15 = b

so ur perpendicular equation is : y = -3x - 15
6 0
3 years ago
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